Câu 1: Tính a. (-1/2xy^2z)(-5/4xyz^2) b. 3/2x^2z+4/5x^2y-1/2x^2y 23/10/2021 Bởi Mackenzie Câu 1: Tính a. (-1/2xy^2z)(-5/4xyz^2) b. 3/2x^2z+4/5x^2y-1/2x^2y
a. $(\dfrac{-1}{2}xy^2z).(\dfrac{-5}{4}xyz^2)$ $=(\dfrac{-1}{2}.\dfrac{-5}{4}).(x.x).(y^2.y).(z.z^2)$ $=\dfrac{5}{8}x^2y^3z^3$ b. $\dfrac{3}{2}x^2z+\dfrac{4}{5}x^2y-\dfrac{1}{2}x^2y$ $=\dfrac{3}{2}x^2z+(\dfrac{4}{5}x^2y-\dfrac{1}{2}x^2y)$ $=\dfrac{3}{2}x^2z+\dfrac{3}{10}x^2y$ Bình luận
a. $(\dfrac{-1}{2}xy^2z).(\dfrac{-5}{4}xyz^2)$
$=(\dfrac{-1}{2}.\dfrac{-5}{4}).(x.x).(y^2.y).(z.z^2)$
$=\dfrac{5}{8}x^2y^3z^3$
b. $\dfrac{3}{2}x^2z+\dfrac{4}{5}x^2y-\dfrac{1}{2}x^2y$
$=\dfrac{3}{2}x^2z+(\dfrac{4}{5}x^2y-\dfrac{1}{2}x^2y)$
$=\dfrac{3}{2}x^2z+\dfrac{3}{10}x^2y$