Câu 13: So sánh P và Q
P = a + {(a – 3) – [( a + 3) – (- a – 2)]}.
Q = [ a + (a + 3)] – [( a + 2) – (a – 2)].
0 bình luận về “Câu 13: So sánh P và Q
P = a + {(a – 3) – [( a + 3) – (- a – 2)]}.
Q = [ a + (a + 3)] – [( a + 2) – (a – 2)].”
P = a + { ( a – 3 ) – [ ( a + 3 ) – ( – a – 2 ) ] } = a + [ a – 3 – ( a + 3 + a + 2 ) ] = a + [ a – 3 – ( 2a + 5 ) ] = a + ( a – 3 -2a – 5 ) = a + ( -8 – a ) = a – 8 – a = -8
Q = [ a – ( a + 3)] – [ ( a + 2 )-(a-2)] = ( a – a + 3 ) – ( a + 2 -a+2 ) = 3 – 4 =-1
P = a + { ( a – 3 ) – [ ( a + 3 ) – ( – a – 2 ) ] }
= a + [ a – 3 – ( a + 3 + a + 2 ) ]
= a + [ a – 3 – ( 2a + 5 ) ]
= a + ( a – 3 -2a – 5 )
= a + ( -8 – a )
= a – 8 – a
= -8
Q = [ a – ( a + 3)] – [ ( a + 2 )-(a-2)]
= ( a – a + 3 ) – ( a + 2 -a+2 )
= 3 – 4
=-1
Ta có: -8 < -1 ⇒ P < Q
P = a + {(a-3) – [(a+3)- (-a-2)]} = a+ [(a-3) – (2a+5)]= -8
Q= [a+(a+3)] – [(a+2) – (a-2)]=3 + 4= 7
Vậy Q>P