Câu 3(3đ): Hoàn thành sơ đồ phản ứng
C2H4(OH)2
↑
C2H6 C2H4 C2H5OH C2H4 C2H5Cl
↓
P.E
Câu 3(3đ): Hoàn thành sơ đồ phản ứng
C2H4(OH)2
↑
C2H6 C2H4 C2H5OH C2H4 C2H5Cl
↓
P.E
$C_2H_6\xrightarrow{t^o,xt}C_2H_4+H_2$
$C_2H_4+H_2O\xrightarrow{H^+}C_2H_5OH$
$C_2H_5OH\xrightarrow{170^oC,H^+}C_2H_4+H_2O$
$3C_2H_4+2KMnO_4+4H_2O\xrightarrow{}3C_2H_4(OH)_2+2KOH+2MnO_2$
$nCH_2=CH_2\xrightarrow{t^o,xt,P}(-CH_2-CH_2-)_n$
$C_2H_4+HCl\xrightarrow{}C_2H_5Cl$
\(\begin{array}{l}
{C_2}{H_6} \to {C_2}{H_4} + {H_2}\\
{C_2}{H_4} + {H_2}O \to {C_2}{H_5}OH\\
{C_2}{H_5}OH \to {C_2}{H_4} + {H_2}O\\
3{C_2}{H_4} + 4{H_2}O + 2KMn{O_4} \to 2KOH + 2Mn{O_2} + 3{C_2}{H_4}{(OH)_2}\\
n(C{H_2} = C{H_2}) \to {( – C{H_2} – C{H_2} – )_n}\\
{C_2}{H_4} + HCl \to {C_2}{H_5}Cl
\end{array}\)