Câu 9. Hoàn thành các chuổi phản ứng sau:
a. CH4 —–> C2H2 —–> C2H4 —–> C2H6 —–> C2H5Cl —–> C2H4.
b. CH4 —–> C2H2 —–> C4H4 —–> C4H6 —–> polibutadien
c. CH4 —–> C2H2 —–> C6H6 —–> C6H5Br
d. C2H6 —–> C2H4 —–> PE
e. CH4 —–> C2H2 —–> Vinyl clorua —–> PVC
$\begin{array}{l} a)\\ 2C{H_4} \to {C_2}{H_2} + 3{H_2}\\ {C_2}{H_2} + {H_2} \to {C_2}{H_4}\\ {C_2}{H_4} + {H_2} \to {C_2}{H_6}\\ {C_2}{H_6} + C{l_2} \to {C_2}{H_5}Cl + HCl\\ {C_2}{H_5}Cl \to {C_2}{H_4} + HCl\\ b)\\ 2C{H_4} \to {C_2}{H_2} + 3{H_2}\\ 2{C_2}{H_2} \to {C_4}{H_4}\\ {C_4}{H_4} + {H_2} \to {C_4}{H_6}\\ n(C{H_2} = CH – CH = C{H_2}) \to {(C{H_2} – CH = CH – C{H_2} – )_n}\\ c)\\ 2C{H_4} \to {C_2}{H_2} + 3{H_2}\\ 3{C_2}{H_2} \to {C_6}{H_6}\\ {C_6}{H_6} + B{r_2} \to {C_6}{H_5}Br + HBr\\ d)\\ {C_2}{H_6} \to {C_2}{H_4} + {H_2}\\ nC{H_2} = C{H_2} \to {( – C{H_2} – C{H_2} – )_n}\\ e)\\ 2C{H_4} \to {C_2}{H_2} + 3{H_2}\\ {C_2}{H_2} + HCl \to {C_2}{H_3}Cl\\ nC{H_2} = CHCl \to {( – C{H_2} – CHCl – )_n} \end{array}$
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\(\begin{array}{l}
a)\\
2C{H_4} \to {C_2}{H_2} + 3{H_2}\\
{C_2}{H_2} + {H_2} \to {C_2}{H_4}\\
{C_2}{H_4} + {H_2} \to {C_2}{H_6}\\
{C_2}{H_6} + C{l_2} \to {C_2}{H_5}Cl + HCl\\
{C_2}{H_5}Cl \to {C_2}{H_4} + HCl\\
b)\\
2C{H_4} \to {C_2}{H_2} + 3{H_2}\\
2{C_2}{H_2} \to {C_4}{H_4}\\
{C_4}{H_4} + {H_2} \to {C_4}{H_6}\\
n(C{H_2} = CH – CH = C{H_2}) \to {(C{H_2} – CH = CH – C{H_2} – )_n}\\
c)\\
2C{H_4} \to {C_2}{H_2} + 3{H_2}\\
3{C_2}{H_2} \to {C_6}{H_6}\\
{C_6}{H_6} + B{r_2} \to {C_6}{H_5}Br + HBr\\
d)\\
{C_2}{H_6} \to {C_2}{H_4} + {H_2}\\
nC{H_2} = C{H_2} \to {( – C{H_2} – C{H_2} – )_n}\\
e)\\
2C{H_4} \to {C_2}{H_2} + 3{H_2}\\
{C_2}{H_2} + HCl \to {C_2}{H_3}Cl\\
nC{H_2} = CHCl \to {( – C{H_2} – CHCl – )_n}
\end{array}\)