Cho 1/7 + 6/7 x (x – 1 3/4)=4. Vậy giá trị của x là: 12/07/2021 Bởi Melody Cho 1/7 + 6/7 x (x – 1 3/4)=4. Vậy giá trị của x là:
$\frac{1}{7}$+$\frac{6}{7}$ × $(x-1\frac{3}{4})=4$ $\frac{6}{7}$ × $(x-1\frac{3}{4})=4-\frac{1}{7}$ $\frac{6}{7}$ × $(x-1\frac{3}{4})=\frac{27}{7}$ $(x-1\frac{3}{4})=\frac{27}{7} :\frac{6}{7}$ $(x-1\frac{3}{4})=\frac{27}{7} ×\frac{7}{6}$ $x-\frac{7}{4}=\frac{9}{2}$ $x=\frac{9}{2}+\frac{7}{4}$ $x=\frac{18}{4}+\frac{7}{4}$ $x=\frac{25}{4}$ Vậy $x=\frac{25}{4}$ Bình luận
`1/7+6/7 × (x-1 3/4)=4` `<=>6/7×(x- 7/4)=27/7` `<=>x-7/4=9/2` `<=>x=9/2+7/4` `<=>x=25/4` Vậy `x=25/4` Bình luận
$\frac{1}{7}$+$\frac{6}{7}$ × $(x-1\frac{3}{4})=4$
$\frac{6}{7}$ × $(x-1\frac{3}{4})=4-\frac{1}{7}$
$\frac{6}{7}$ × $(x-1\frac{3}{4})=\frac{27}{7}$
$(x-1\frac{3}{4})=\frac{27}{7} :\frac{6}{7}$
$(x-1\frac{3}{4})=\frac{27}{7} ×\frac{7}{6}$
$x-\frac{7}{4}=\frac{9}{2}$
$x=\frac{9}{2}+\frac{7}{4}$
$x=\frac{18}{4}+\frac{7}{4}$
$x=\frac{25}{4}$
Vậy $x=\frac{25}{4}$
`1/7+6/7 × (x-1 3/4)=4`
`<=>6/7×(x- 7/4)=27/7`
`<=>x-7/4=9/2`
`<=>x=9/2+7/4`
`<=>x=25/4`
Vậy `x=25/4`