cho A=1+x+x^2+x^3 +….+x^49.cmr:Ax-A=x^50-1 giúp mk vs………5 sao 18/08/2021 Bởi Arya cho A=1+x+x^2+x^3 +….+x^49.cmr:Ax-A=x^50-1 giúp mk vs………5 sao
Đáp án+Giải thích các bước giải: `A=1+x^2+x^3+x^4+…+x^49` `⇒A.x=x+x^2+x^3+x^4+…+x^50` `→Ax-A=(x+x^2+x^3+x^4+…+x^50)-(1+x^2+x^3+x^4+…+x^49)` ` =x^50-1` Vậy `Ax-A=x^50-1 ` (đpcm) Bình luận
`A=1+x+x^2+x^3 +….+x^49` =>`Ax =x+x^2+x^3 +….+x^49 + x^50` =>`Ax – A = (x+x^2+x^3 +….+x^49 + x^50) – (1+x+x^2+x^3 +….+x^49)` =>`Ax – A = x+x^2+x^3 +….+x^49 + x^50 – 1-x-x^2-x^3-…-x^49` =>`Ax – A = (x-x)+(x^2 – x^2)+(x^3-x^3)+…+(x^49-x^49) + x^50 – 1` =>`Ax – A = 0 + 0 + 0 +…+ 0 + x^50 – 1` =>`Ax – A = x^50 – 1` (đpcm) Bình luận
Đáp án+Giải thích các bước giải:
`A=1+x^2+x^3+x^4+…+x^49`
`⇒A.x=x+x^2+x^3+x^4+…+x^50`
`→Ax-A=(x+x^2+x^3+x^4+…+x^50)-(1+x^2+x^3+x^4+…+x^49)`
` =x^50-1`
Vậy `Ax-A=x^50-1 ` (đpcm)
`A=1+x+x^2+x^3 +….+x^49`
=>`Ax =x+x^2+x^3 +….+x^49 + x^50`
=>`Ax – A = (x+x^2+x^3 +….+x^49 + x^50) – (1+x+x^2+x^3 +….+x^49)`
=>`Ax – A = x+x^2+x^3 +….+x^49 + x^50 – 1-x-x^2-x^3-…-x^49`
=>`Ax – A = (x-x)+(x^2 – x^2)+(x^3-x^3)+…+(x^49-x^49) + x^50 – 1`
=>`Ax – A = 0 + 0 + 0 +…+ 0 + x^50 – 1`
=>`Ax – A = x^50 – 1` (đpcm)