Cho A = 3^1+3^2+3^3+….+3^2018+3^2019. Tìm số dư nếu A chia 4 Giúp mình với !!! CẢM ƠN BẸN NHA :)) 30/11/2021 Bởi Madeline Cho A = 3^1+3^2+3^3+….+3^2018+3^2019. Tìm số dư nếu A chia 4 Giúp mình với !!! CẢM ƠN BẸN NHA :))
A=3^1+3^2+3^3=…+3^2018+3^2019 A=3^1+3^2+3^3+(3^4+3^5+3^6+3^7)+(3^8+3^9+3^10+3^11)…+(3^2016+3^2017+3^2018+3^2019) A=39+3^4.(1+3+3^2+3^3)+3^8.(1+3+3^2+3^3)+…+3^2016.(1+3+3^2+3^3) A=39+3^4.40+3^8.40+…+3^2016.40 A=40.(3^4+3^8+…+3^2016)+39 :4 dư 3 Bình luận
Đáp án: `A=3^1+3^2+3^3=…+3^2018+3^2019` `A=3^1+3^2+3^3+(3^4+3^5+3^6+3^7)+(3^8+3^9+3^10+3^11)…+(3^2016+3^2017+3^2018+3^2019)` `A=39+3^4.(1+3+3^2+3^3)+3^8.(1+3+3^2+3^3)+…+3^2016.(1+3+3^2+3^3)` `A=39+3^4.40+3^8.40+…+3^2016.40` `A=40.(3^4+3^8+…+3^2016)+39 : 4 dư 3` Giải thích các bước giải: Bình luận
A=3^1+3^2+3^3=…+3^2018+3^2019
A=3^1+3^2+3^3+(3^4+3^5+3^6+3^7)+(3^8+3^9+3^10+3^11)…+(3^2016+3^2017+3^2018+3^2019)
A=39+3^4.(1+3+3^2+3^3)+3^8.(1+3+3^2+3^3)+…+3^2016.(1+3+3^2+3^3)
A=39+3^4.40+3^8.40+…+3^2016.40
A=40.(3^4+3^8+…+3^2016)+39 :4 dư 3
Đáp án:
`A=3^1+3^2+3^3=…+3^2018+3^2019`
`A=3^1+3^2+3^3+(3^4+3^5+3^6+3^7)+(3^8+3^9+3^10+3^11)…+(3^2016+3^2017+3^2018+3^2019)`
`A=39+3^4.(1+3+3^2+3^3)+3^8.(1+3+3^2+3^3)+…+3^2016.(1+3+3^2+3^3)`
`A=39+3^4.40+3^8.40+…+3^2016.40`
`A=40.(3^4+3^8+…+3^2016)+39 : 4 dư 3`
Giải thích các bước giải: