Cho A = 4x²y² – xy² + y² – xy + 2 B = x²y² + 4xy² – 2y² + 1 a, Tính C = A + B b, Tính P = C + A + B 13/09/2021 Bởi Charlie Cho A = 4x²y² – xy² + y² – xy + 2 B = x²y² + 4xy² – 2y² + 1 a, Tính C = A + B b, Tính P = C + A + B
a)C = A + B C=4x²y² – xy² + y² – xy + 2+x²y² + 4xy² – 2y² + 1 =4x²y²+x²y²- xy²+4xy²+ y²- 2y²- xy+ 1+ 2 =5x²y²+3xy²- y²-xy+3 b) P = C + A + B P=5x²y²+3xy²- y²-xy+3+4x²y² – xy² + y² – xy + 2+x²y² + 4xy² – 2y² + 1 =5x²y²+4x²y²+x²y²+3xy² – xy²+ 4xy²- y² + y²- 2y²-xy – xy+3+ 2 + 1 =10x²y²+6xy²-2y²-2xy+6 Bình luận
a)C = A + B
C=4x²y² – xy² + y² – xy + 2+x²y² + 4xy² – 2y² + 1
=4x²y²+x²y²- xy²+4xy²+ y²- 2y²- xy+ 1+ 2
=5x²y²+3xy²- y²-xy+3
b) P = C + A + B
P=5x²y²+3xy²- y²-xy+3+4x²y² – xy² + y² – xy + 2+x²y² + 4xy² – 2y² + 1
=5x²y²+4x²y²+x²y²+3xy² – xy²+ 4xy²- y² + y²- 2y²-xy – xy+3+ 2 + 1
=10x²y²+6xy²-2y²-2xy+6