Cho a+b+c = 0; x+y+z=0; a/x +b/y +c/z = 0 CMR ax ² + by ² + cz ² = 0 12/10/2021 Bởi Elliana Cho a+b+c = 0; x+y+z=0; a/x +b/y +c/z = 0 CMR ax ² + by ² + cz ² = 0
`bossthai02` Từ `x+y+z=0` `⇒x^2=(y+z)^2, y^2=(x+z)^2, z^2=(x+y)^2` Mặt khác : `ax^2+by^2+cz^2` `=a(y+z)^2+b(x+z)^2+c(x+y)^2` `=a(y^2+2yz+z^2)+b(x^2+2xz+z^2)+c(x^2+2yx+x^2)` `=x^2(b+c)+y^2(a+c)+z^2(a+b)+2(ayz+bxz+cxy)` `=-(ax^2+by^2+cz^2)+2(ayz+bxz+cxy)` mà ` ayz+bxz+cxy=0( vìa/x +b/y +c/z = 0)` `⇒ ax^2+by^2+cz^2=-ax^2-by^2-cz^2` `⇒ 2(ax^2+by^2+cz^2)=0` `⇒(ax^2+by^2+cz^2)=0` Bình luận
`bossthai02`
Từ `x+y+z=0`
`⇒x^2=(y+z)^2, y^2=(x+z)^2, z^2=(x+y)^2`
Mặt khác :
`ax^2+by^2+cz^2`
`=a(y+z)^2+b(x+z)^2+c(x+y)^2`
`=a(y^2+2yz+z^2)+b(x^2+2xz+z^2)+c(x^2+2yx+x^2)`
`=x^2(b+c)+y^2(a+c)+z^2(a+b)+2(ayz+bxz+cxy)`
`=-(ax^2+by^2+cz^2)+2(ayz+bxz+cxy)`
mà ` ayz+bxz+cxy=0( vìa/x +b/y +c/z = 0)`
`⇒ ax^2+by^2+cz^2=-ax^2-by^2-cz^2`
`⇒ 2(ax^2+by^2+cz^2)=0`
`⇒(ax^2+by^2+cz^2)=0`