cho đa thức
P(x)=5x^5 +3x -4x^4 -2x^3 +3x^2 +6
Q(x)=2x^4 -2x -x +3x^2 -2x^3 +1/4
tính p(x)+q(x)
p(x)-q(x)
mik đang cần gấp mong mn giúp cảm ơn
cho đa thức
P(x)=5x^5 +3x -4x^4 -2x^3 +3x^2 +6
Q(x)=2x^4 -2x -x +3x^2 -2x^3 +1/4
tính p(x)+q(x)
p(x)-q(x)
mik đang cần gấp mong mn giúp cảm ơn
P (x)=$5x^{5}$+3x-4$x^{4}$-2$x^{3}$+3$x^{2}$ +6
⇒P (x)=$5x^{5}$-4$x^{4}$-2$x^{3}$+3$x^{2}$+3x+6
Q (x)=2$x^{4}$-2x-x+3$x^{2}$-2$x^{3}$+$\frac{1}{4}$
=2$x^{4}$+(-2x-x)+3$x^{2}$-2$x^{3}$+$\frac{1}{4}$
=2$x^{4}$-3x+3$x^{2}$-2$x^{3}$+$\frac{1}{4}$
⇒Q (x)=2$x^{4}$-2$x^{3}$+3$x^{2}$-3x+$\frac{1}{4}$
P (x)=$5x^{5}$-4$x^{4}$-2$x^{3}$+3$x^{2}$+3x+6
+
Q (x)= 2$x^{4}$-2$x^{3}$+3$x^{2}$-3x+$\frac{1}{4}$
P(x)+Q(x)=$5x^{5}$-2$x^{4}-4$x^{3}+6$x^{2}$ +6,25
P (x)=$5x^{5}$-4$x^{4}$-2$x^{3}$+3$x^{2}$+3x+6
–
Q (x)= 2$x^{4}$-2$x^{3}$+3$x^{2}$-3x+$\frac{1}{4}$
P(x)-Q(x)=$5x^{5}$-6$x^{4}$ +6x+5,75
no name
xin hay nhất nha
`#DyHungg`
`P(x)+Q(x)=5x^5+3x-4x^4-2x^3+3x^2+6+2x^4-2x-x+3x^2-2x^3+1/4`
`=5x^5+(-4x^4+2x^4)+(-2x^3-2x^3)+(+3x-3x)+(3x^2+3x^2)+(6+1/4)`
`=5x^5-2x^4-4x^3+6x^2+25/4`
`P(x)-Q(x)=5x^5+3x-4x^4-2x^3+3x^2+6-2x^4+2x+x-3x^2+2x^3-1/4`
`=5x^5+(-4x^4-2x^4)+(-2x^3+2x^3)+(+3x+3x)+(3x^2-3x^2)+(6-1/4)`
`=5x^5-6x^4+6x+23/4`