Cho S= 1- 1/2 + 1/3 – 1/4 +….+ 1/2011 – 1/2012 + 1/2013 P= 1/1007 + 1/1008 +….+ 1/2012 + 1/2013 Tính (S-P)^2013

By Mary

Cho S= 1- 1/2 + 1/3 – 1/4 +….+ 1/2011 – 1/2012 + 1/2013
P= 1/1007 + 1/1008 +….+ 1/2012 + 1/2013
Tính (S-P)^2013

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  1. Đáp án:

    Ta có :

    `S = 1- 1/2 + 1/3 – 1/4 +….+ 1/2011 – 1/2012 + 1/2013`

    `S = (1+1/3+1/5+…+1/2013)-(1/2+1/4+1/6+…+1/2012)`

    `S = (1+1/2+1/3+1/4+1/5+…+1/2013)-2(1/2+1/4+…+1/2012)`

    `S = (1+1/2+1/3+1/4+1/5+…+1/2013)-(1+1/2+…+1/1006)`

    `S = 1/1007+1/1008+1/1009+…+1/2013 = P`

    `->` S – P = (1/1007+1/1008+1/1009+…+1/2013)-(1/1007+1/1008+1/1009+…+1/2013) = 0`

    `-> (S-P)^2013 = 0^2013=0`

    `Go od luck!`

    Có thắc mắc thì hỏi 

     

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