Cho y=1/3x^3 -mx^2-x+m+2/3 có đồ thị (cm).tìm m để (cm) cắt ox tại 3 điểm phân biệt x1,x2,x3 tm x1^2+x2^2+x3^2>15
Cho y=1/3x^3 -mx^2-x+m+2/3 có đồ thị (cm).tìm m để (cm) cắt ox tại 3 điểm phân biệt x1,x2,x3 tm x1^2+x2^2+x3^2>15
Đáp án:
\(m \in \left( { – \infty ; – 1} \right) \cup \left( {1; + \infty } \right)\)
Giải thích các bước giải:
\(\eqalign{
& y = {1 \over 3}{x^3} – m{x^2} – x + m + {2 \over 3} \cr
& Xet\,\,PTHDGD:\,\,{1 \over 3}{x^3} – m{x^2} – x + m + {2 \over 3} = 0 \cr
& \Leftrightarrow {x^3} – 3m{x^2} – 3x + 3m + 2 = 0\,\,\left( 1 \right) \cr
& \Leftrightarrow \left( {x – 1} \right)\left( {{x^2} + \left( {1 – 3m} \right)x – 2 – 3m} \right) = 0 \cr
& \Leftrightarrow \left[ \matrix{
{x_1} = 1 \hfill \cr
{x^2} + \left( {1 – 3m} \right)x – 2 – 3m = 0\,\,\left( 2 \right) \hfill \cr} \right. \cr
& De\,DTHS\,\,cat\,\,truc\,\,hoanh\,\,tai\,\,3\,\,diem\,\,pb \cr
& \Rightarrow \left( 1 \right)\,\,co\,\,3\,\,nghiem\,\,pb \cr
& \Rightarrow \left( 2 \right)\,\,co\,\,2\,\,nghiem\,\,pb\,\,khac\,\,\,1 \cr
& \Rightarrow \left\{ \matrix{
\Delta = {\left( {1 – 3m} \right)^2} + 4\left( {2 + 3m} \right) > 0 \hfill \cr
1 + 1 – 3m – 2 – 3m \ne 0 \hfill \cr} \right. \cr
& \Leftrightarrow \left\{ \matrix{
9{m^2} – 6m + 1 + 8 + 6m > 0 \hfill \cr
– 6m \ne 0 \hfill \cr} \right. \cr
& \Leftrightarrow \left\{ \matrix{
9{m^2} + 9 > 0\,\,\left( {luon\,dung} \right) \hfill \cr
m \ne 0 \hfill \cr} \right. \Leftrightarrow m \ne 0 \cr
& Goi\,\,{x_2},\,\,{x_3}\,\,la\,\,2\,\,nghiem\,\,pb\,\,cua\,\,\left( 2 \right) \cr
& Ap\,\,dung\,\,DL\,\,Vi – et\,\,ta\,\,co:\,\,\left\{ \matrix{
{x_1} + {x_2} = 3m – 1 \hfill \cr
{x_1}{x_2} = – 2 – 3m \hfill \cr} \right. \cr
& Theo\,\,bai\,\,ra\,\,ta\,\,co: \cr
& x_1^2 + x_2^2 + x_3^2 > 15 \cr
& \Leftrightarrow 1 + {\left( {{x_1} + {x_2}} \right)^2} – 2{x_1}{x_2} > 15 \cr
& \Leftrightarrow {\left( {3m – 1} \right)^2} – 2\left( { – 2 – 3m} \right) > 14 \cr
& \Leftrightarrow 9{m^2} – 6m + 1 + 4 + 6m > 14 \cr
& \Leftrightarrow 9{m^2} > 9 \cr
& \Leftrightarrow \left[ \matrix{
m > 1 \hfill \cr
m < - 1 \hfill \cr} \right.\,\,\left( {tm\,\,m \ne 0} \right) \cr & Vay\,\,m \in \left( { - \infty ; - 1} \right) \cup \left( {1; + \infty } \right) \cr} \)