cho z= e ^ (x-2y) , x=sin t , y=t ^ 3 . Tính dz/dt theo t 25/08/2021 Bởi Charlie cho z= e ^ (x-2y) , x=sin t , y=t ^ 3 . Tính dz/dt theo t
Ta có $z’ = (e^{x-2y})’$ $= e^{x-2y} . (x-2y)’$$= e^{x-2y} . (\sin t – 2t^3)’$ $=e^{\sin t – 2t^3} (\cos t – 6t^2)$ Vậy $z’ = e^{\sin t – 2t^3} (\cos t – 6t^2)$ Bình luận
Ta có
$z’ = (e^{x-2y})’$
$= e^{x-2y} . (x-2y)’$
$= e^{x-2y} . (\sin t – 2t^3)’$
$=e^{\sin t – 2t^3} (\cos t – 6t^2)$
Vậy
$z’ = e^{\sin t – 2t^3} (\cos t – 6t^2)$