Chứng minh: sin6x*sin4x -sin15x*sin13x + in19x*sin9x=0 28/08/2021 Bởi Claire Chứng minh: sin6x*sin4x -sin15x*sin13x + in19x*sin9x=0
Ta có: `\qquad sin6xsin4x-sin15xsin13x+sin19xsin9x` `=1/2[cos(6x-4x)-cos(6x+4x)]-1/2[cos(15x-13x)-cos(15x+13x)]+1/2[cos(19x-9x)-cos(19x+9x)]` `=1/2(cos2x-cos10x)-1/2(cos2x-cos28x)+1/2(cos10x-cos28x)` `=1/2cos2x-1/2cos10x-1/2cos2x+1/2cos28x+1/2cos10x-1/2cos28x` `=0` Vậy: `sin6xsin4x-sin15xsin13x+sin19xsin9x=0` Bình luận
Ta có:
`\qquad sin6xsin4x-sin15xsin13x+sin19xsin9x`
`=1/2[cos(6x-4x)-cos(6x+4x)]-1/2[cos(15x-13x)-cos(15x+13x)]+1/2[cos(19x-9x)-cos(19x+9x)]`
`=1/2(cos2x-cos10x)-1/2(cos2x-cos28x)+1/2(cos10x-cos28x)`
`=1/2cos2x-1/2cos10x-1/2cos2x+1/2cos28x+1/2cos10x-1/2cos28x`
`=0`
Vậy: `sin6xsin4x-sin15xsin13x+sin19xsin9x=0`