CM:các ps sau=nhau a;41/88;4141/8888;414141/888888 b;27425-27/99900;27425425-27425/99900000

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1. Giải thích các bước giải:

   `a)`
   Ta có:
   `41/88=(41:1)/(88:1)=41/88`
   `4141/8888=(4141:101)/(8888:101)=41/88`
   `414141/888888=(414141:10101)/(888888:10101)=41/88`
   Vì `41=41=41=>41/88=41/88=41/88=>41/88=4141/8888=414141/888888`
   Vậy `41/88=4141/8888=414141/888888`
   `b)`
   Ta có:
   `(27425-27)/99900=27398/99900`
   `(27425425-27425)/99900000=27398000/99900000=(27398000:1000)/(99900000:1000)=27398/99900`
   Vì `27398=27398=>27398/99900=27398/99900=>(27425-27)/99900=(27425425-27425)/99900000`
   Vậy `(27425-27)/99900=(27425425-27425)/99900000`

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2. `a,` Ta có :

   `41/88=41/88`

   `4141/8888=[41.101]/[88.101]=41/88`

   `414141/888888=[41.10101]/[88.10101]=41/88`

   `=> 41/88=4141/8888=414141/888888`

   `b,` Ta có :
   `[27425-27]/99900=[27425-27]/9990`

   `[27425425-27425]/99900000=[(27425000+425)-(27000+425)]/99900000=[27425000-27000]/99900000=[(27425-27).1000]/[99900.1000]=[27425-27]/99900`

   `=> [27425-27]/99900=[27425425-27425]/99900000`

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