$\color{black}{\frac{4}{9}.\frac{13}{3}-\frac{4}{9}.\frac{40}{9}+\frac{8}{182}}$

$\color{black}{\frac{4}{9}.\frac{13}{3}-\frac{4}{9}.\frac{40}{9}+\frac{8}{182}}$

0 bình luận về “$\color{black}{\frac{4}{9}.\frac{13}{3}-\frac{4}{9}.\frac{40}{9}+\frac{8}{182}}$”

  1. Đáp án:

    $\text{ $\dfrac{4}{9}$ . $\dfrac{13}{3}$ – $\dfrac{4}{9}$ . $\dfrac{40}{9}$ + $\dfrac{8}{182}$}$

     $\text{= $\dfrac{4}{9} $. ( $\dfrac{13}{3}$ – $\dfrac{40}{9}$) + $\dfrac{4}{91}$ }$

     $\text{= $\dfrac{4}{9}$ . (-$\dfrac{1}{9}$) + $\dfrac{8}{91}$ }$

    $\text{ = $\dfrac{-4}{81}$ + $\dfrac{8}{91}$ }$

      $\text{= $\dfrac{-364}{7371}$  + $\dfrac{324}{7371}$ }$

     $\text{= $\dfrac{-40}{7371}$ }$

     

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  2. = $\dfrac{4}{9}$ . `(`$\dfrac{13}{3}$ – $\dfrac{40}{9}$`)` + $\dfrac{8}{182}$

    = $\dfrac{4}{9}$ . $\dfrac{-1}{9}$ + $\dfrac{8}{182}$

    = $\dfrac{-4}{81}$ + $\dfrac{8}{182}$

    = $\dfrac{-40}{7131}$

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