dấu “/” là phần ak -5/6-x=7/12+(-1)/3 HELP ME !!! 23/11/2021 Bởi Serenity dấu “/” là phần ak -5/6-x=7/12+(-1)/3 HELP ME !!!
`(-5)/6 – x = 7/12 + (-1)/3` `⇒ -x = 7/12 – 1/3 + 5/6` `⇒ -x = 7/12 – 4/12 + 10/12` `⇒ -x = 13/12` `⇒ x = (-13)/12` Bình luận
$\dfrac{-5}{6}-$x=$\dfrac{7}{12}+\dfrac{-1}{3}$ $⇔ \dfrac{-5}{6}-x=\dfrac{7}{12}+\dfrac{-4}{12}$ $⇔ \dfrac{-5}{6}-x=\dfrac{7+(-4)}{12}$ $⇔ \dfrac{-5}{6}-x =\dfrac{3}{12}$ $⇔$ $x = \dfrac{-5}{6}-\dfrac{3}{12}$ $⇔$ $x = \dfrac{-10}{12}-\dfrac{3}{12}$ $⇔$ $x=\dfrac{-13}{12}$ Vậy $x=\dfrac{-13}{12}$ Bình luận
`(-5)/6 – x = 7/12 + (-1)/3`
`⇒ -x = 7/12 – 1/3 + 5/6`
`⇒ -x = 7/12 – 4/12 + 10/12`
`⇒ -x = 13/12`
`⇒ x = (-13)/12`
$\dfrac{-5}{6}-$x=$\dfrac{7}{12}+\dfrac{-1}{3}$
$⇔ \dfrac{-5}{6}-x=\dfrac{7}{12}+\dfrac{-4}{12}$
$⇔ \dfrac{-5}{6}-x=\dfrac{7+(-4)}{12}$
$⇔ \dfrac{-5}{6}-x =\dfrac{3}{12}$
$⇔$ $x = \dfrac{-5}{6}-\dfrac{3}{12}$
$⇔$ $x = \dfrac{-10}{12}-\dfrac{3}{12}$
$⇔$ $x=\dfrac{-13}{12}$
Vậy $x=\dfrac{-13}{12}$