$\dfrac{(\dfrac{11^2}{200}+0,415):\dfrac{1}{1000}}{\dfrac{1}{12}-37,25+3\dfrac{1}{6}}$

By Liliana

$\dfrac{(\dfrac{11^2}{200}+0,415):\dfrac{1}{1000}}{\dfrac{1}{12}-37,25+3\dfrac{1}{6}}$




Viết một bình luận