Xét tính chẵn lẻ Y = |x+1 | – |x-1|/ |x+1 | + | x-1| 06/07/2021 Bởi Camila Xét tính chẵn lẻ Y = |x+1 | – |x-1|/ |x+1 | + | x-1|
$D=\mathbb{R}$ $f(-x)=\dfrac{|-x+1|-|-x-1|}{|-x+1|+|-x-1|}$ $=\dfrac{|x-1|-|x+1|}{|x-1|+|x+1|}$ $=-f(x)$ $\to f(x)$ lẻ Bình luận
`y = (|x + 1| – |x – 1|)/(|x + 1| + |x – 1|)` `D = RR` `y (-x)` `= (|-(x – 1)| – |-(x + 1)|)/(|-(x – 1)| + |-(x + 1)|)` `= (|x – 1| – |x + 1|)/(|x – 1| + |x + 1|)` `= -y` `=>` Hàm số lẻ Bình luận
$D=\mathbb{R}$
$f(-x)=\dfrac{|-x+1|-|-x-1|}{|-x+1|+|-x-1|}$
$=\dfrac{|x-1|-|x+1|}{|x-1|+|x+1|}$
$=-f(x)$
$\to f(x)$ lẻ
`y = (|x + 1| – |x – 1|)/(|x + 1| + |x – 1|)`
`D = RR`
`y (-x)`
`= (|-(x – 1)| – |-(x + 1)|)/(|-(x – 1)| + |-(x + 1)|)`
`= (|x – 1| – |x + 1|)/(|x – 1| + |x + 1|)`
`= -y`
`=>` Hàm số lẻ