Toán F,|x-1/3|+1=7/3 G,(3x-1)²-2=7 H,(5x-2)³+1=28 I,(x-2/3)²+1/6=5/18 22/11/2021 By Samantha F,|x-1/3|+1=7/3 G,(3x-1)²-2=7 H,(5x-2)³+1=28 I,(x-2/3)²+1/6=5/18
f) |x – 1/3| + 1 = 7/3 `⇔ |x – 1/3| = 7/3 – 1` `⇔ |x – 1/3| = 4/3` ⇔ \(\left[ \begin{array}{l}x-1/3=4/3\\x-1/3=-4/3\end{array} \right.\) ⇔ \(\left[ \begin{array}{l}x=5/3\\x=-1\end{array} \right.\) Vậy x = 5/3 hoặc x = -1. `g) (3x – 1)² – 2 = 7` `⇔ (3x – 1)² = 9` `⇔ 3x – 1 = √9` ⇔ \(\left[ \begin{array}{l}3x-1=3\\3x-1=-3\end{array} \right.\) ⇔ \(\left[ \begin{array}{l}x=4/3\\x=-2/3\end{array} \right.\) Vậy x = 4/3 hoặc x = -2/3 `h) (5x – 2)³ + 1 = 28` `⇔ (5x – 2)³ = 27` `⇔ (5x – 2)³ = 3³` `⇔ 5x – 2 = 3` `⇔ 5x = 5` `⇔ x = 1` Vậy x = 1 `i) (x – 2/3)² + 1/6 = 5/18` `⇔ (x – 2/3)² = 1/9` `⇔ x – 2/3 = √1/9` ⇔ \(\left[ \begin{array}{l}x-2/3=1/3\\x-2/3=-1/3\end{array} \right.\) ⇔ \(\left[ \begin{array}{l}x=1\\x=1/3\end{array} \right.\) Vậy x = 1 hoặc x = 1/3. Trả lời
$\begin{array}{l}\underline{\text{Đáp án:}}\\\underline{\text{Giải thích các bước giải:}}\\f,|x-1/3|+1=7/3\\→|x-1/3|=7/3-1\\→|x-1/3|=4/3\\→\left[ \begin{array}{l}x-1/3=4/3\\x-1/3=-4/3\end{array} \right.→\left[ \begin{array}{l}x=5/3\\x=-1\end{array} \right.\\Vậy \,\, x=-1 \,\, hoặc \,\, x=5/3\\g,(3x-1)^2-2=7\\→(3x-1)^2=9\\→\left[ \begin{array}{l}3x-1=3\\3x-1=-3\end{array} \right.\\→\left[ \begin{array}{l}3x=4\\3x=-2\end{array} \right.\\→\left[ \begin{array}{l}x=4/3\\x=-2/3\end{array} \right.\\Vậy \,\, x=4/3 \,\, hoặc \,\, x=-2/3\\h,(5x-2)^3+1=28\\→(5x-2)^3=27\\→(5x-2)^3=3^3\\→5x-2=3\\→5x=5\\→x=1\\Vậy \,\, x=1\\i,(x-2/3)^2+1/6=5/18\\→(x-2/3)^2=5/18-1/6\\→(x-2/3)^2=2/18\\→(x-2/3)^2=1/9\\→\left[ \begin{array}{l}x-2/3=1/3\\x-2/3=-1/3\end{array} \right.\\→\left[ \begin{array}{l}x=1\\x=1/3\end{array} \right.\\Vậy \,\, x=1 \,\, hoặc \,\, x=1/3\\\underline{\text{CHÚC BẠN HỌC TỐT}}\\\end{array}$ Trả lời
f) |x – 1/3| + 1 = 7/3
`⇔ |x – 1/3| = 7/3 – 1`
`⇔ |x – 1/3| = 4/3`
⇔ \(\left[ \begin{array}{l}x-1/3=4/3\\x-1/3=-4/3\end{array} \right.\)
⇔ \(\left[ \begin{array}{l}x=5/3\\x=-1\end{array} \right.\)
Vậy x = 5/3 hoặc x = -1.
`g) (3x – 1)² – 2 = 7`
`⇔ (3x – 1)² = 9`
`⇔ 3x – 1 = √9`
⇔ \(\left[ \begin{array}{l}3x-1=3\\3x-1=-3\end{array} \right.\)
⇔ \(\left[ \begin{array}{l}x=4/3\\x=-2/3\end{array} \right.\)
Vậy x = 4/3 hoặc x = -2/3
`h) (5x – 2)³ + 1 = 28`
`⇔ (5x – 2)³ = 27`
`⇔ (5x – 2)³ = 3³`
`⇔ 5x – 2 = 3`
`⇔ 5x = 5`
`⇔ x = 1`
Vậy x = 1
`i) (x – 2/3)² + 1/6 = 5/18`
`⇔ (x – 2/3)² = 1/9`
`⇔ x – 2/3 = √1/9`
⇔ \(\left[ \begin{array}{l}x-2/3=1/3\\x-2/3=-1/3\end{array} \right.\)
⇔ \(\left[ \begin{array}{l}x=1\\x=1/3\end{array} \right.\)
Vậy x = 1 hoặc x = 1/3.
$\begin{array}{l}\underline{\text{Đáp án:}}\\\underline{\text{Giải thích các bước giải:}}\\f,|x-1/3|+1=7/3\\→|x-1/3|=7/3-1\\→|x-1/3|=4/3\\→\left[ \begin{array}{l}x-1/3=4/3\\x-1/3=-4/3\end{array} \right.→\left[ \begin{array}{l}x=5/3\\x=-1\end{array} \right.\\Vậy \,\, x=-1 \,\, hoặc \,\, x=5/3\\g,(3x-1)^2-2=7\\→(3x-1)^2=9\\→\left[ \begin{array}{l}3x-1=3\\3x-1=-3\end{array} \right.\\→\left[ \begin{array}{l}3x=4\\3x=-2\end{array} \right.\\→\left[ \begin{array}{l}x=4/3\\x=-2/3\end{array} \right.\\Vậy \,\, x=4/3 \,\, hoặc \,\, x=-2/3\\h,(5x-2)^3+1=28\\→(5x-2)^3=27\\→(5x-2)^3=3^3\\→5x-2=3\\→5x=5\\→x=1\\Vậy \,\, x=1\\i,(x-2/3)^2+1/6=5/18\\→(x-2/3)^2=5/18-1/6\\→(x-2/3)^2=2/18\\→(x-2/3)^2=1/9\\→\left[ \begin{array}{l}x-2/3=1/3\\x-2/3=-1/3\end{array} \right.\\→\left[ \begin{array}{l}x=1\\x=1/3\end{array} \right.\\Vậy \,\, x=1 \,\, hoặc \,\, x=1/3\\\underline{\text{CHÚC BẠN HỌC TỐT}}\\\end{array}$