`f, (2^{4}.5^{2}.11^{2}.7) : (2^{3}.5^{3}.7^{2}.11)`
`g, (2^{10}.3^{10} – 2^{10}.3^{9}) : (2^{9}.3^{10})`
`h, (11.3^{22}.3^{7} – 9^{15}) : (2.3^{14})^{2}`
`i, (5^{11}.7^{12} + 5^{11}.7^{11}) : (5^{12}.7^{11} + 9.5^{11}.7^{11})`
`f, (2^{4}.5^{2}.11^{2}.7) : (2^{3}.5^{3}.7^{2}.11)`
`g, (2^{10}.3^{10} – 2^{10}.3^{9}) : (2^{9}.3^{10})`
`h, (11.3^{22}.3^{7} – 9^{15}) : (2.3^{14})^{2}`
`i, (5^{11}.7^{12} + 5^{11}.7^{11}) : (5^{12}.7^{11} + 9.5^{11}.7^{11})`
Đáp án: f ) $\frac{22}{35}$
g ) $\frac{4}{3}$
h ) 6
i ) $\frac{4}{7}$
Giải thích các bước giải:
f ) ($2^{4}$ . $5^{2}$ . $11^{2}$ . 7 ) : ( $2^{3}$ . $5^{3}$ . $7^{2}$ . 11 )
= [ $2^{3}$ . $5^{2}$ . 11 . 7 ( 2 . 11 ) ] : [ $2^{3}$ . $5^{2}$ . 11 . 7 ( 5 . 7 ) ]
= 22 : 35
= $\frac{22}{35}$
g ) ( $2^{10}$ . $3^{10}$ – $2^{10}$ . $3^{9}$ ) : ( $2^{9}$ . $3^{10}$ )
= [ $2^{9}$ . $3^{9}$ . ( 2 . 3 – 2 ) ] : ( $2^{9}$ . $3^{9}$ . 3 )
= 4 : 3
= $\frac{4}{3}$
h ) ( 11 . $3^{22}$ . $3^{7}$ – $9^{15}$ ) : ( 2 . $3^{14}$ )^2
= ( 11 . $3^{22}$ . $3^{7}$ – $3^{30}$ ) : 4 . $3^{28}$
= ( 11 . $3^{29}$ – $3^{30}$ ) : 4 . $3^{28}$
= [ $3^{28}$ ( 11 . 3 – $3^{2}$ ) ] : ( $3^{28}$ . 4 )
= ( 33 – 9 ) : 4
= 24 : 4
= 6
i ) ( $5^{11}$ . $7^{12}$ + $5^{11}$ . $7^{11}$ ) : ( $5^{12}$ . $7^{11}$ + 9 . $5^{11}$ . $7^{11}$ )
= [ $5^{11}$ . $7^{11}$ ( 7 + 1 ) ] : [ $5^{11}$ . $7^{11}$ ( 5 + 9 )
= 8 : 14
= $\frac{8}{14}$
= $\frac{4}{7}$
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