Fe ——> FeCl2 <=> FeCl3 ——> NaCl ——–> NaOH ———> NaClO

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1. Em tham khảo nha :

   \(\begin{array}{l}
   Fe + 2HCl \to FeC{l_2} + {H_2}\\
   2FeC{l_2} + C{l_2} \to 2FeC{l_3}\\
   2FeC{l_3} + Cu \to CuC{l_2} + 2FeC{l_2}\\
   FeC{l_3} + 3NaOH \to Fe{(OH)_3} + 3NaCl\\
   2NaCl + 2{H_2}O \xrightarrow{dpcmn} C{l_2} + {H_2} + 2NaOH\\
   NaOH + HClO \to NaClO + {H_2}O
   \end{array}\)

    

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2. Đáp án:

   `Fe+2HCl →FeCl_2 +H_2`

   `2FeCl_2+Cl_2→2FeCl_3`

   `FeCl_3+3NaOH→Fe(OH)_3+3NaCl`

   `2NaCl+2H_2O→2NaOH+H_2+Cl_2`

   `2NaOH+Cl_2→NaCl+NaClO+H_2O`

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