$\frac{1}{2}$ x+1 + $\frac{1}{4}$ x+3m= 3- $\frac{1}{3}$ x+2

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1.  

   Giải thích các bước giải:

    $\dfrac{1}{2}x+1+\dfrac{1}{4}x + 3m – 3-\dfrac{1}{3}Ữ+2$

   $\to \dfrac{x}{2} + \dfrac{x}{4} + \dfrac{x}{3} = 4-3m$

   $\to \dfrac{13x}{12} = 4-3m$

   $\to 13x = 12.(4-3m)$

   $\to x= \dfrac{12.(4-3m)}{13}$

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2. `1/2x+1+1/4x+3m=3-1/3x+2`

   `<=>1/2x+1/4x+1/3x+3m=3+2-1`

   `<=>x(1/2+1/4+1/3)+3m=4`

   `<=>13/12x+3m=4`

   `<=>13/12x=4-3m`

   `<=>x=(4-3m):13/12`

   `<=>x=(48-36m)/13`

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