Toán ( $\frac{1}{2.3}$ + $\frac{1}{3.4}$ + … + $\frac{1}{49.50}$ )x = 1 28/07/2021 By Athena ( $\frac{1}{2.3}$ + $\frac{1}{3.4}$ + … + $\frac{1}{49.50}$ )x = 1
`( 1/( 2 . 3 ) + 1/( 3 . 4 ) + …. + 1/( 49 . 50 ) ) . x = 1` `⇔ ( 1/2 – 1/3 + 1/3 – 1/4 + …. + 1/49 – 1/50 ) . x = 1` `⇔ ( 1/2 – 1/50 ) . x = 1` `⇔ 12/25 . x = 1` `⇔ x = 1 : 12/25` `⇔ x = 25/12` Vậy , `x = 25/12 .` Trả lời
Đáp án + Giải thích các bước giải: `(1/2.3+1/3.4+1/4.5+…+1/49.50)x=1` `=>(1/2-1/3+1/3-1/4+1/4-1/5+…+1/49-1/50)x=1` `=>(1/2-1/50)x=1` `=>(25/50-1/50)x=1` `=>12/25.x=1` `=>x=1:12/25` `=>x=1. 25/12` `=>x=25/12` Vậy `x=25/12` Trả lời
`( 1/( 2 . 3 ) + 1/( 3 . 4 ) + …. + 1/( 49 . 50 ) ) . x = 1`
`⇔ ( 1/2 – 1/3 + 1/3 – 1/4 + …. + 1/49 – 1/50 ) . x = 1`
`⇔ ( 1/2 – 1/50 ) . x = 1`
`⇔ 12/25 . x = 1`
`⇔ x = 1 : 12/25`
`⇔ x = 25/12`
Vậy , `x = 25/12 .`
Đáp án + Giải thích các bước giải:
`(1/2.3+1/3.4+1/4.5+…+1/49.50)x=1`
`=>(1/2-1/3+1/3-1/4+1/4-1/5+…+1/49-1/50)x=1`
`=>(1/2-1/50)x=1`
`=>(25/50-1/50)x=1`
`=>12/25.x=1`
`=>x=1:12/25`
`=>x=1. 25/12`
`=>x=25/12`
Vậy `x=25/12`