Toán $\frac{1}{3}$ .$\sqrt[]{9x+9}$ +2.$\sqrt[]{x+1}$ +20. $\sqrt[]{4x+4}$ /25 =1 20/07/2021 By Elliana $\frac{1}{3}$ .$\sqrt[]{9x+9}$ +2.$\sqrt[]{x+1}$ +20. $\sqrt[]{4x+4}$ /25 =1
Đáp án: Giải thích các bước giải: $\dfrac{1}{3}\sqrt{9(x+1)}+2\sqrt{x+1}+20.\sqrt{\dfrac{4(x+1)}{25}}=1$ $⇔\sqrt{x+1}+2\sqrt{x+1}+8\sqrt{x+1}=1$ $⇔11\sqrt{x+1}=1$ $⇔\sqrt{x+1}=\dfrac{1}{11}$ $⇔x+1=\dfrac{1}{121}$ $⇔x=\dfrac{-120}{121}$ Trả lời