Toán $\frac{11}{12}$ .x+ $\frac{3}{4}$ = $\frac{-1}{6}$ 10/09/2021 By Piper $\frac{11}{12}$ .x+ $\frac{3}{4}$ = $\frac{-1}{6}$
$\frac{11}{12}$ . x + $\frac{3}{4}$ = $\frac{-1}{6}$ $\frac{11}{12}$ . x = $\frac{-1}{6}$ – $\frac{3}{4}$ $\frac{11}{12}$ . x = $\frac{-11}{12}$ => x = -1 Trả lời
$\frac{11}{12}$ . x + $\frac{3}{4}$ = $\frac{-1}{6}$
$\frac{11}{12}$ . x = $\frac{-1}{6}$ – $\frac{3}{4}$
$\frac{11}{12}$ . x = $\frac{-11}{12}$
=> x = -1
Đáp án:
x = – 1
Giải thích các bước giải: