|$\frac{-11}{15}$ +x|-$\frac{40}{23}$ =$\frac{-17}{23}$ | $\frac{-11}{15}$ +x| -$\frac{40}{23}$ = $\frac{-17}{23}$

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1. Đáp án:

   `x\in{26/15;-4/15}`

   Giải thích các bước giải:

   `|(-11)/15+x|-40/23=(-17)/23`
   `=>|(-11)/15+x|=-17/23+40/23`
   `=>|(-11)/15+x|=23/23`
   `=>|(-11)/15+x|=1`
   `=>`\(\left[ \begin{array}{l}\dfrac{-11}{15}+x=1\\\dfrac{-11}{15}+x=-1\end{array} \right.\) 
   `=>`\(\left[ \begin{array}{l}x=1+\dfrac{11}{15}\\x=-1+\dfrac{11}{15}\end{array} \right.\) 
   `=>`\(\left[ \begin{array}{l}x=\dfrac{15}{15}+\dfrac{11}{15}\\x=\dfrac{-15}{15}+\dfrac{11}{15}\end{array} \right.\)
   `=>`\(\left[ \begin{array}{l}x=\dfrac{26}{15}\\x=\dfrac{-4}{15}\end{array} \right.\)
   Vậy `x\in{26/15;-4/15}`

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2. Đáp án:

    

   Giải thích các bước giải:

    `|(-11)/15+x|-40/23=(-17)/23`

   `|(-11)/15+x|=-17/23+40/23`

   `|(-11)/15+x|=1`

   `\(\left[ \begin{array}{l}\dfrac{-11}{15}+x=1\\\dfrac{-11}{15}+x=-1\end{array} \right.\) `

   `\(\left[ \begin{array}{l}x=1 + \dfrac{11}{15}\\\ x = -1+\dfrac{-11}{15}\end{array} \right.\) `

   `\(\left[ \begin{array}{l}x=\dfrac{26}{15}\\ x =\dfrac{-4}{15}\end{array} \right.\) `

   vậy `x \in{26/15;-4/15}`

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