$\frac{x+2}{x+1}$+$\frac{2}{y-2}$=6 $\frac{5}{x+1}$-$\frac{1}{y-2}$ =3 03/07/2021 Bởi Melanie $\frac{x+2}{x+1}$+$\frac{2}{y-2}$=6 $\frac{5}{x+1}$-$\frac{1}{y-2}$ =3
Đáp án: $\begin{array}{l}\left\{ \begin{array}{l}\frac{{x + 2}}{{x + 1}} + \frac{2}{{y – 2}} = 6\\\frac{5}{{x + 1}} – \frac{1}{{y – 2}} = 3\end{array} \right. \Rightarrow \left\{ \begin{array}{l}1 + \frac{1}{{x + 1}} + \frac{2}{{y – 2}} = 6\\5.\frac{1}{{x + 1}} – \frac{1}{{y – 2}} = 3\end{array} \right.\\ \Rightarrow \left\{ \begin{array}{l}\frac{1}{{x + 1}} + 2.\frac{1}{{y – 2}} = 5\\5.\frac{1}{{x + 1}} – \frac{1}{{y – 2}} = 3\end{array} \right. \Rightarrow \left\{ \begin{array}{l}\frac{1}{{x + 1}} = 1\\\frac{1}{{y – 2}} = 2\end{array} \right.\\ \Rightarrow \left\{ \begin{array}{l}x + 1 = 1\\y – 2 = \frac{1}{2}\end{array} \right. \Rightarrow \left\{ \begin{array}{l}x = 0\\y = \frac{5}{2}\end{array} \right.\end{array}$ Bình luận
Đáp án:
$\begin{array}{l}
\left\{ \begin{array}{l}
\frac{{x + 2}}{{x + 1}} + \frac{2}{{y – 2}} = 6\\
\frac{5}{{x + 1}} – \frac{1}{{y – 2}} = 3
\end{array} \right. \Rightarrow \left\{ \begin{array}{l}
1 + \frac{1}{{x + 1}} + \frac{2}{{y – 2}} = 6\\
5.\frac{1}{{x + 1}} – \frac{1}{{y – 2}} = 3
\end{array} \right.\\
\Rightarrow \left\{ \begin{array}{l}
\frac{1}{{x + 1}} + 2.\frac{1}{{y – 2}} = 5\\
5.\frac{1}{{x + 1}} – \frac{1}{{y – 2}} = 3
\end{array} \right. \Rightarrow \left\{ \begin{array}{l}
\frac{1}{{x + 1}} = 1\\
\frac{1}{{y – 2}} = 2
\end{array} \right.\\
\Rightarrow \left\{ \begin{array}{l}
x + 1 = 1\\
y – 2 = \frac{1}{2}
\end{array} \right. \Rightarrow \left\{ \begin{array}{l}
x = 0\\
y = \frac{5}{2}
\end{array} \right.
\end{array}$
Đáp án: