$\frac{x-214}{86}$+$\frac{x-132}{84}$+$\frac{x-54}{82}$=6 Tìm x 07/07/2021 Bởi Remi $\frac{x-214}{86}$+$\frac{x-132}{84}$+$\frac{x-54}{82}$=6 Tìm x
Đáp án: $x = 300$ Giải thích các bước giải: $\begin{array}{l}\dfrac{{x – 214}}{{86}} + \dfrac{{x – 132}}{{84}} + \dfrac{{x – 54}}{{82}} = 6\\ \Leftrightarrow \left( {\dfrac{x}{{86}} + \dfrac{x}{{84}} + \dfrac{x}{{82}}} \right) = 6 + \dfrac{{214}}{{86}} + \dfrac{{132}}{{84}} + \dfrac{{54}}{{82}}\\ \Leftrightarrow x\left( {\dfrac{1}{{86}} + \dfrac{1}{{84}} + \dfrac{1}{{82}}} \right) = 6 + \dfrac{{107}}{{43}} + \dfrac{{11}}{7} + \dfrac{{27}}{{41}}\\ \Leftrightarrow x.\dfrac{{21164}}{{592368}} = \dfrac{{132275}}{{12341}}\\ \Leftrightarrow x = \dfrac{{132275}}{{12341}}.\dfrac{{592368}}{{21164}}\\ \Leftrightarrow x = 300\end{array}$ Vậy $x = 300$ Bình luận
Đáp án:
$x = 300$
Giải thích các bước giải:
$\begin{array}{l}
\dfrac{{x – 214}}{{86}} + \dfrac{{x – 132}}{{84}} + \dfrac{{x – 54}}{{82}} = 6\\
\Leftrightarrow \left( {\dfrac{x}{{86}} + \dfrac{x}{{84}} + \dfrac{x}{{82}}} \right) = 6 + \dfrac{{214}}{{86}} + \dfrac{{132}}{{84}} + \dfrac{{54}}{{82}}\\
\Leftrightarrow x\left( {\dfrac{1}{{86}} + \dfrac{1}{{84}} + \dfrac{1}{{82}}} \right) = 6 + \dfrac{{107}}{{43}} + \dfrac{{11}}{7} + \dfrac{{27}}{{41}}\\
\Leftrightarrow x.\dfrac{{21164}}{{592368}} = \dfrac{{132275}}{{12341}}\\
\Leftrightarrow x = \dfrac{{132275}}{{12341}}.\dfrac{{592368}}{{21164}}\\
\Leftrightarrow x = 300
\end{array}$
Vậy $x = 300$