$\frac{3}{2}$ – $\frac{1}{2}$ . / x-3/ = $\frac{1}{4}$ 25/08/2021 Bởi Isabelle $\frac{3}{2}$ – $\frac{1}{2}$ . / x-3/ = $\frac{1}{4}$
Đáp án: Giải thích các bước giải: $\dfrac{3}{2}-\dfrac{1}{2}.|x-3|=\dfrac{1}{4}$ $ $ $⇒\dfrac{1}{2}.|x-3|=\dfrac{5}{4}$ $ $ $⇒ $⇒|x-3|=\dfrac{5}{2}$ $ $ $⇒$\(\left[ \begin{array}{l}x-3=\frac{5}{2}\\x-3=\frac{-5}{2}\end{array} \right.\) ⇒\(\left[ \begin{array}{l}x=\frac{11}{2}\\x=\frac{1}{2}\end{array} \right.\) Bình luận
` 3/2 – 1/2 . |x-3| = 1/4` `⇔ 1/2 . |x-3| = 5/4` `⇔ |x-3| = 5/2` `⇒` \(\left[ \begin{array}{l}x=\dfrac{11}{2}\\x=\dfrac{1}{2}\end{array} \right.\) Vậy $x$ $∈$ `{{11}/2;1/2}` Bình luận
Đáp án:
Giải thích các bước giải:
$\dfrac{3}{2}-\dfrac{1}{2}.|x-3|=\dfrac{1}{4}$
$ $
$⇒\dfrac{1}{2}.|x-3|=\dfrac{5}{4}$
$ $
$⇒
$⇒|x-3|=\dfrac{5}{2}$
$ $
$⇒$\(\left[ \begin{array}{l}x-3=\frac{5}{2}\\x-3=\frac{-5}{2}\end{array} \right.\) ⇒\(\left[ \begin{array}{l}x=\frac{11}{2}\\x=\frac{1}{2}\end{array} \right.\)
` 3/2 – 1/2 . |x-3| = 1/4`
`⇔ 1/2 . |x-3| = 5/4`
`⇔ |x-3| = 5/2`
`⇒` \(\left[ \begin{array}{l}x=\dfrac{11}{2}\\x=\dfrac{1}{2}\end{array} \right.\)
Vậy $x$ $∈$ `{{11}/2;1/2}`