g, 2.(x-1) + 3(x-2) = x -4 h, 3.(4 – x) – 2.( x- 1) = x + 20 i, 3(x – 2) + 2x = 10

0 bình luận về “g, 2.(x-1) + 3(x-2) = x -4 h, 3.(4 – x) – 2.( x- 1) = x + 20 i, 3(x – 2) + 2x = 10”

1. g, 2.(x-1) + 3(x-2) = x -4

   ⇔2x-2+3x-6=x-4

   ⇔2x+3x-x=2+6-4

   ⇔4x=4

   ⇔x=1

   h, 3.(4 – x) – 2.( x- 1) = x + 20

   ⇔12-3x-2x+2=x+20

   ⇔-3x-2x-x=20-12-2

   ⇔-6x=6

   x=-1

   i, 3(x – 2) + 2x = 10

   ⇔3x-6+2x=10

   ⇔3x+2x=10+6

   ⇔5x=16

   ⇔x=16/5

    

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2. Đáp án:

    

   Giải thích các bước giải:

   g, 2.(x-1) + 3(x-2) = x -4

   ⇔2x – 2 + 3x – 6 -x + 4 = 0

   ⇔4x – 4 = 0

   ⇔ x = 1

   h, 3.(4 – x) – 2.( x- 1) = x + 20

   ⇔12 – 3x – 2x + 2 – x – 20 = 0

   ⇔-6x -6 = 0

   ⇔ -6x = 6

   ⇔ x = -1

   i, 3(x – 2) + 2x = 10

   ⇔3x – 6 + 2x = 0

   ⇔5x – 6 =0

   ⇔ x = $\frac{6}{5}$ 

   $chucbanhoktot$

   $chomikxinctlhnnha$

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