g(x)=4x^2+3x+1, h(x)=3x^2-2x-3, tìm f(x)=g(x)-h(x) 21/08/2021 Bởi Melanie g(x)=4x^2+3x+1, h(x)=3x^2-2x-3, tìm f(x)=g(x)-h(x)
Đáp án: $\text{f(x) = g(x) – h(x) }$ $f(x) = 4x^2 +3x +1 -(3x^2 -2x -3)$ $f(x) = 4x^2 +3x +1 -3x^2 +2x +3 $ $f(x) = x^2 +5x +4$ $\text{Vậy f(x) = x^2 +5x +4 }$ Bình luận
$f(x)=g(x)-h(x)=(4x^2+3x+1)-(3x^2-2x-3) \\=4x^2+3x+1-3x^2+2x+3 \\=x^2+5x+4$
Đáp án:
$\text{f(x) = g(x) – h(x) }$
$f(x) = 4x^2 +3x +1 -(3x^2 -2x -3)$
$f(x) = 4x^2 +3x +1 -3x^2 +2x +3 $
$f(x) = x^2 +5x +4$
$\text{Vậy f(x) = x^2 +5x +4 }$