Toán Gấp nhanh tui đi học b) (3x- 15)(6- 2x) = 0 14/09/2021 By Sadie Gấp nhanh tui đi học b) (3x- 15)(6- 2x) = 0
`(3x – 15)(6 – 2x)=0` `⇒` \(\left[ \begin{array}{l}3x-15=0\\6-2x = 0\end{array} \right.\) `⇒` \(\left[ \begin{array}{l}3x=15\\2x=6\end{array} \right.\) `⇒` \(\left[ \begin{array}{l}x=5\\x=3\end{array} \right.\) Trả lời
Đáp án: x ∈ { 3, 5} Giải thích các bước giải: Ta có: (3x- 15)(6- 2x) = 0 =>\(\left[ \begin{array}{l}3x-15=0\\6-2x=0\end{array} \right.\) => \(\left[ \begin{array}{l}3x=15\\2x=6\end{array} \right.\) => \(\left[ \begin{array}{l}x=15 : 3\\x=6 : 2\end{array} \right.\) => \(\left[ \begin{array}{l}x=5\\x=3\end{array} \right.\) Vậy x ∈ { 3, 5} Trả lời
`(3x – 15)(6 – 2x)=0`
`⇒` \(\left[ \begin{array}{l}3x-15=0\\6-2x = 0\end{array} \right.\)
`⇒` \(\left[ \begin{array}{l}3x=15\\2x=6\end{array} \right.\)
`⇒` \(\left[ \begin{array}{l}x=5\\x=3\end{array} \right.\)
Đáp án: x ∈ { 3, 5}
Giải thích các bước giải:
Ta có: (3x- 15)(6- 2x) = 0
=>\(\left[ \begin{array}{l}3x-15=0\\6-2x=0\end{array} \right.\)
=> \(\left[ \begin{array}{l}3x=15\\2x=6\end{array} \right.\)
=> \(\left[ \begin{array}{l}x=15 : 3\\x=6 : 2\end{array} \right.\)
=> \(\left[ \begin{array}{l}x=5\\x=3\end{array} \right.\)
Vậy x ∈ { 3, 5}