giải bất phương trình sau a, (x-1)(x+2)<(x-1)2+3 b, (x+1)^2+2x^2<(2x+3)^2-(x-3)^2 c,2x(x-7)+(3-x)^2>3(x+1)^2 help me 19/11/2021 Bởi Melody giải bất phương trình sau a, (x-1)(x+2)<(x-1)2+3 b, (x+1)^2+2x^2<(2x+3)^2-(x-3)^2 c,2x(x-7)+(3-x)^2>3(x+1)^2 help me
a) (x-1)(x+2) < (x-1)²+3 ⇔x²+2x-x-2 < x²-2x+1+3 ⇔3x <6 ⇔x<2 b) (x+1)²+2x² < (2x+3)²- (x-3)² ⇔x²+2x+1+2x²<4x²+12x+9 – x²+6x-9 ⇔ -16x< -1 ⇔ x> $\frac{1}{16}$ c) 2x(x-7) +(3-x)²>3.(x+1)² ⇔2x²-14x+9-6x+x²>3(x²+2x+1) ⇔3x²-20x+9>3x²+6x+3 ⇔ -26x> -6 ⇔ x< $\frac{3}{13}$ Bình luận
a) (x-1)(x+2) < (x-1)²+3
⇔x²+2x-x-2 < x²-2x+1+3
⇔3x <6
⇔x<2
b) (x+1)²+2x² < (2x+3)²- (x-3)²
⇔x²+2x+1+2x²<4x²+12x+9 – x²+6x-9
⇔ -16x< -1
⇔ x> $\frac{1}{16}$
c) 2x(x-7) +(3-x)²>3.(x+1)²
⇔2x²-14x+9-6x+x²>3(x²+2x+1)
⇔3x²-20x+9>3x²+6x+3
⇔ -26x> -6
⇔ x< $\frac{3}{13}$