Giải các phương trình sau: 2x(3x+6)=0 3+2x=0 6x-(3x+2).(3x+2)=0 08/08/2021 Bởi Ariana Giải các phương trình sau: 2x(3x+6)=0 3+2x=0 6x-(3x+2).(3x+2)=0
2x(3x+6)=0 <=>6x^2+12x=0 <=>6x(x+2)=0 TH1: 6x=0 <=>x=0 (0 thoả mãn) TH2: x+2=0 <=>x=-2 Vậy S={-2} 3+2x=0 <=>2x=-3 <=>x=-3/2 Vậy S ={-3/2} 6x-(3x+2).(3x+2)=0 (6x-1).(3x+2)=0 TH1: 6x-1=0 <=>6x=1 <=>x=1/6 TH2: 3x+2=0 <=>3x=-2 <=>x=-2/3 Vậy S={-2/3} #Creative Team Name Bình luận
`2x(3x+6)=0` `⇔x(x+2)3=0` `⇔x(x+2)=0` `⇔`\(\left[ \begin{array}{l}x=0\\x+2=0\end{array} \right.\) `⇔`\(\left[ \begin{array}{l}x=0\\x=-2\end{array} \right.\) `3+2x=0` `⇔2x=-3` `⇔x=-3/2` `6x-(3x+2).(3x+2)=0` `⇔6x-9x^2-6x-6x-4=0` `⇔-9x^2-6x-4=0` `⇔9x^2+6x+4=0` `⇔(3x+1)^2+3=0` `⇒`vô nghiệm Bình luận
2x(3x+6)=0
<=>6x^2+12x=0
<=>6x(x+2)=0
TH1: 6x=0
<=>x=0 (0 thoả mãn)
TH2: x+2=0
<=>x=-2
Vậy S={-2}
3+2x=0
<=>2x=-3
<=>x=-3/2
Vậy S ={-3/2}
6x-(3x+2).(3x+2)=0
(6x-1).(3x+2)=0
TH1: 6x-1=0
<=>6x=1
<=>x=1/6
TH2: 3x+2=0
<=>3x=-2
<=>x=-2/3
Vậy S={-2/3}
#Creative Team Name
`2x(3x+6)=0`
`⇔x(x+2)3=0`
`⇔x(x+2)=0`
`⇔`\(\left[ \begin{array}{l}x=0\\x+2=0\end{array} \right.\)
`⇔`\(\left[ \begin{array}{l}x=0\\x=-2\end{array} \right.\)
`3+2x=0`
`⇔2x=-3`
`⇔x=-3/2`
`6x-(3x+2).(3x+2)=0`
`⇔6x-9x^2-6x-6x-4=0`
`⇔-9x^2-6x-4=0`
`⇔9x^2+6x+4=0`
`⇔(3x+1)^2+3=0`
`⇒`vô nghiệm