Giải các phương trình sau:
a, $\frac{3x+2}{2}$ – $\frac{3x+1}{6}$ = $\frac{5}{3}$ + 2x
b, $\frac{x+4}{5}$ – x + 4 = $\frac{x}{3}$ – $\frac{x-2}{2}$
c, $\frac{4x+3}{5}$ – $\frac{6x-2}{7}$ = $\frac{5x+4}{3}$ +3
d, $\frac{5x+2}{6}$ – $\frac{8x-1}{3}$ = $\frac{4x+2}{5}$ – 5
Đáp án:
`a)-5/6`
`b)6`
`c)-2`
`d)2`
Giải thích các bước giải:
`a)( 3x+2)/2 – (3x+1)/6 = 5/3 + 2x`
`⇔3(3x+2)−3x−1=10+12x`
`⇔9x+6−3x−1=10+12x`
`⇔6x+5=10+12x`
`⇔6x=-5`
`⇔x=-5/6`
`b)(x+4)/5 – x +4 = x/3 – (x-2)/2`
`⇔6(x+4)−30x+120=10x−15(x−2)`
`⇔6x+24−30x+120=10x−15x+30`
`⇔19x=114`
`⇔x=6`
`c)(4x+3)/5 – ( 6x-2)/7 = (5x+4)/3 + 3`
`⇔21(4x+3)−30(3x−1)=35(5x+4)+315`
`⇔84x+63−90x+30=175x+140+315`
`⇔181x=−362`
`⇔x=-2`
`d)(5x+2)/6 – ( 8x-1)/3 = (4x+2)/5 -5`
`⇔5(5x+2)−10(8x−1)=12(2x+1)−150`
`⇔25x+10−80x+10=24x+12−150`
`⇔79x=158`
`⇔x=2`
Đáp án:
Giải thích các bước giải:
a, 3(3x+2)-(3x+1)=10+12x
9x+6-3x-1=10+12x
-6x=5
x=-5/6
b, 6(x+4)-30x+120=10x-15(x-2)
6x+24-30x+120=10x-15x+30
-24x+144=-5x+30
-19x=-144
x=6
c, 7(4x-3)-6(6x-2)=14(5x+4)+126
28x+21-36x+12=70x+56+126
_8x+33=70x+182
-78x=149
x=-149/78
d, 5(5x-2)-10(8x-1)=6(4x+2)-150
25x+10-80x+10=24x+12-150
-79x=-158
x=2
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