Giải giúp mìn với mn owiiii : a, 1.2.3…9 – 1.2.3….8 – 1.2.3…..7.8^2 b, (3.4.2^16)^2/ 11.2^13.4^11- 16^9 c, 125.(-61).(-2)^3 .(-1) ^2n (n thuộc N

a)

$1.2.3…9 – 1.2.3…8 – 1.2.3…7.8²$

$= 1.2.3…8.(9-1) – 1.2.3…7.8²$

$= 1.2.3…7.8.8 – 1.2.3…7.8²$

$= 0$

b)

$\dfrac{(3.4.2^{16})²}{11.2^{13}.4^{11}-16^{9}}$

$= \dfrac{(3.2².2^{16})²}{11.2^{13}.2^{22}-2^{36}}$

$= \dfrac{(3.2^{18})²}{11.2^{35}-2^{36}}$

$= \dfrac{3².2^{36}}{2^{35}(11-2)}$

$= \dfrac{9.2^{36}}{2^{35}.9}$

$ = 2$

c)

$125.(-61).(-2)³.(-1)^{2n}$

$=125.(-61).(-8).1$

$= (-1000).(-61)$

$= 61000$