Giải giúp mình /x/=3 /x-5/=6 /2x-1/+1=8 /x+2/=3 Cám mơn

a, ${|x|=3}$

⇒ \(\left[ \begin{array}{l}x=3\\x=-3\end{array} \right.\) 

b, ${|x-5|=6}$

⇒ \(\left[ \begin{array}{l}x-5=6\\x-5=-6\end{array} \right.\)  ⇒ \(\left[ \begin{array}{l}x=11\\x=-1\end{array} \right.\) 

c, ${|2x-1|+1=8}$

    ${|2x-1|    = 8-1}$

    ${|2x-1|    =7}$

⇒ \(\left[ \begin{array}{l}2x-1=7\\2x-1=-7\end{array} \right.\) ⇒ \(\left[ \begin{array}{l}2x=8\\2x=-6\end{array} \right.\) ⇒ \(\left[ \begin{array}{l}x=4\\x=-3\end{array} \right.\) 

d, ${|x+2|=3}$

⇒ \(\left[ \begin{array}{l}x+2=3\\x+2=-3\end{array} \right.\) ⇒ \(\left[ \begin{array}{l}x=1\\x=-5\end{array} \right.\)