Giải giúp mình /x/=3 /x-5/=6 /2x-1/+1=8 /x+2/=3 Cám mơn 18/10/2021 Bởi Lydia Giải giúp mình /x/=3 /x-5/=6 /2x-1/+1=8 /x+2/=3 Cám mơn
a, ${|x|=3}$ ⇒ \(\left[ \begin{array}{l}x=3\\x=-3\end{array} \right.\) b, ${|x-5|=6}$ ⇒ \(\left[ \begin{array}{l}x-5=6\\x-5=-6\end{array} \right.\) ⇒ \(\left[ \begin{array}{l}x=11\\x=-1\end{array} \right.\) c, ${|2x-1|+1=8}$ ${|2x-1| = 8-1}$ ${|2x-1| =7}$ ⇒ \(\left[ \begin{array}{l}2x-1=7\\2x-1=-7\end{array} \right.\) ⇒ \(\left[ \begin{array}{l}2x=8\\2x=-6\end{array} \right.\) ⇒ \(\left[ \begin{array}{l}x=4\\x=-3\end{array} \right.\) d, ${|x+2|=3}$ ⇒ \(\left[ \begin{array}{l}x+2=3\\x+2=-3\end{array} \right.\) ⇒ \(\left[ \begin{array}{l}x=1\\x=-5\end{array} \right.\) Bình luận
a, ${|x|=3}$
⇒ \(\left[ \begin{array}{l}x=3\\x=-3\end{array} \right.\)
b, ${|x-5|=6}$
⇒ \(\left[ \begin{array}{l}x-5=6\\x-5=-6\end{array} \right.\) ⇒ \(\left[ \begin{array}{l}x=11\\x=-1\end{array} \right.\)
c, ${|2x-1|+1=8}$
${|2x-1| = 8-1}$
${|2x-1| =7}$
⇒ \(\left[ \begin{array}{l}2x-1=7\\2x-1=-7\end{array} \right.\) ⇒ \(\left[ \begin{array}{l}2x=8\\2x=-6\end{array} \right.\) ⇒ \(\left[ \begin{array}{l}x=4\\x=-3\end{array} \right.\)
d, ${|x+2|=3}$
⇒ \(\left[ \begin{array}{l}x+2=3\\x+2=-3\end{array} \right.\) ⇒ \(\left[ \begin{array}{l}x=1\\x=-5\end{array} \right.\)
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