giải hệ phương trình x+y=90 10/x-10/y=1/20 27/07/2021 Bởi Josephine giải hệ phương trình x+y=90 10/x-10/y=1/20
Đáp án: $\left( {x;y} \right) = \left( {40;50} \right);\left( {450; – 360} \right)$ Giải thích các bước giải: $\begin{array}{l}\left\{ \begin{array}{l}x + y = 90\\\frac{{10}}{x} – \frac{{10}}{y} = \frac{1}{{20}}\end{array} \right.\left( {x;y \ne 0} \right)\\ \Rightarrow \left\{ \begin{array}{l}x = 90 – y\\\frac{1}{x} – \frac{1}{y} = \frac{1}{{200}}\end{array} \right.\\ \Rightarrow \left\{ \begin{array}{l}x = 90 – y\\\frac{{y – x}}{{xy}} = \frac{1}{{200}}\end{array} \right.\\ \Rightarrow \left\{ \begin{array}{l}x = 90 – y\\\frac{{y – \left( {90 – y} \right)}}{{y\left( {90 – y} \right)}} = \frac{1}{{200}}\left( 1 \right)\end{array} \right.\\\left( 1 \right) \Rightarrow 200\left( {2y – 90} \right) = 90y – {y^2}\\ \Rightarrow {y^2} + 310y – 18000 = 0\\ \Rightarrow \left[ \begin{array}{l}y = 50\\y = – 360\end{array} \right.\left( {tm} \right)\\ \Rightarrow \left[ \begin{array}{l}y = 50;x = 90 – y = 40\\y = – 360;x = 90 – y = 450\end{array} \right.\\ \Rightarrow \left( {x;y} \right) = \left( {40;50} \right);\left( {450; – 360} \right)\end{array}$ Bình luận
Đáp án: $\left( {x;y} \right) = \left( {40;50} \right);\left( {450; – 360} \right)$
Giải thích các bước giải:
$\begin{array}{l}
\left\{ \begin{array}{l}
x + y = 90\\
\frac{{10}}{x} – \frac{{10}}{y} = \frac{1}{{20}}
\end{array} \right.\left( {x;y \ne 0} \right)\\
\Rightarrow \left\{ \begin{array}{l}
x = 90 – y\\
\frac{1}{x} – \frac{1}{y} = \frac{1}{{200}}
\end{array} \right.\\
\Rightarrow \left\{ \begin{array}{l}
x = 90 – y\\
\frac{{y – x}}{{xy}} = \frac{1}{{200}}
\end{array} \right.\\
\Rightarrow \left\{ \begin{array}{l}
x = 90 – y\\
\frac{{y – \left( {90 – y} \right)}}{{y\left( {90 – y} \right)}} = \frac{1}{{200}}\left( 1 \right)
\end{array} \right.\\
\left( 1 \right) \Rightarrow 200\left( {2y – 90} \right) = 90y – {y^2}\\
\Rightarrow {y^2} + 310y – 18000 = 0\\
\Rightarrow \left[ \begin{array}{l}
y = 50\\
y = – 360
\end{array} \right.\left( {tm} \right)\\
\Rightarrow \left[ \begin{array}{l}
y = 50;x = 90 – y = 40\\
y = – 360;x = 90 – y = 450
\end{array} \right.\\
\Rightarrow \left( {x;y} \right) = \left( {40;50} \right);\left( {450; – 360} \right)
\end{array}$
Đáp án:
Giải thích các bước giải: