giai p/t (2+can5) x+y=3-can5 -x + 2y=6 – 2can5 giup minh vs 04/12/2021 Bởi Mackenzie giai p/t (2+can5) x+y=3-can5 -x + 2y=6 – 2can5 giup minh vs
$\Large\left \{ {{(2 +√5)x + y = 3- √5} \atop {-x + 2y = 6- 2√5}} \right.$ <=> $\Large\left \{ {{(4 +2√5)x + 2y = 6- 2√5} \atop {-x + 2y = 6- 2√5}} \right.$ <=> $\Large\left \{ {{(4 +2√5)x + 2y = 6- 2√5} \atop {(4 +2√5+1)x = 0}} \right.$ <=> $\Large\left \{ {{(4 +2√5)x + 2y = 6- 2√5} \atop {x = 0}} \right.$ <=> $\Large\left \{ {{0 + 2y = 6- 2√5} \atop {x = 0}} \right.$ <=> $\Large\left \{ {{y = (6- 2√5)/2} \atop {x = 0}} \right.$ <=> $\Large\left \{ {{y = 3- √5} \atop {x = 0}} \right.$ Bình luận
$\Large\left \{ {{(2 +√5)x + y = 3- √5} \atop {-x + 2y = 6- 2√5}} \right.$
<=> $\Large\left \{ {{(4 +2√5)x + 2y = 6- 2√5} \atop {-x + 2y = 6- 2√5}} \right.$
<=> $\Large\left \{ {{(4 +2√5)x + 2y = 6- 2√5} \atop {(4 +2√5+1)x = 0}} \right.$
<=> $\Large\left \{ {{(4 +2√5)x + 2y = 6- 2√5} \atop {x = 0}} \right.$
<=> $\Large\left \{ {{0 + 2y = 6- 2√5} \atop {x = 0}} \right.$
<=> $\Large\left \{ {{y = (6- 2√5)/2} \atop {x = 0}} \right.$
<=> $\Large\left \{ {{y = 3- √5} \atop {x = 0}} \right.$