Giải phương trình: 4/x^2+2x-3=2x-5/x+3-2x/x-1 29/10/2021 Bởi Isabelle Giải phương trình: 4/x^2+2x-3=2x-5/x+3-2x/x-1
$\dfrac{4}{x²+2x-3}=\dfrac{2x-5}{x+3}-\dfrac{2x}{x-1}$ $↔\dfrac{4}{(x-1)(x+3)}=\dfrac{(2x-5)(x-1)}{x+3}-\dfrac{2x(x+3)}{(x-1)(x+3)}$ $↔4=2x²-7x+5-2x²-6x$ $↔-1=-13x$ $↔\dfrac{1}{13}=x$ Bình luận
$\dfrac{4}{x²+2x-3}=\dfrac{2x-5}{x+3}-\dfrac{2x}{x-1}$
$↔\dfrac{4}{(x-1)(x+3)}=\dfrac{(2x-5)(x-1)}{x+3}-\dfrac{2x(x+3)}{(x-1)(x+3)}$
$↔4=2x²-7x+5-2x²-6x$
$↔-1=-13x$
$↔\dfrac{1}{13}=x$