giải phương trình a) 7/x+2+2/x+3=1/x ²+5x+6 b)4/x-2+x/x+1=x ²-2/x ²-x-2 c)x/x+2-x ²+1/x ²-2x-8=3/x-4 d) x/2x+1-2/x-3=x ²+5/2x ²-5x-3

giải phương trình
a) 7/x+2+2/x+3=1/x ²+5x+6
b)4/x-2+x/x+1=x ²-2/x ²-x-2
c)x/x+2-x ²+1/x ²-2x-8=3/x-4
d) x/2x+1-2/x-3=x ²+5/2x ²-5x-3

0 bình luận về “giải phương trình a) 7/x+2+2/x+3=1/x ²+5x+6 b)4/x-2+x/x+1=x ²-2/x ²-x-2 c)x/x+2-x ²+1/x ²-2x-8=3/x-4 d) x/2x+1-2/x-3=x ²+5/2x ²-5x-3”

  1. `a)`

     `7/(x+2)+2/(x+3)=1/(x²+5x+6)`     `(`ĐKXĐ `x\ne -2` ;`x \ne -3“)`

    `⇔  (7(x+3)+2(x+2))/((x+2).(x+3))=1/((x+2)(x+3))`

    `⇒ 7x + 21+2x+4=1`

    `⇔ 9x +25 =1`

    `⇔ 9x=-24`

    `⇔ x= (-8)/3` `(TMĐK)`

    `b)`

    `4/(x-2)+x/(x+1)=(x²-2)/(x²-x-2)`    `(`ĐKXĐ `x\ne -1` ;`x \ne 2“)`

    `⇔(4(x+1)+x(x-2))/((x-2)(x+1))=(x²-2)/((x+1)(x-2))`

    `⇒ 4x +4 + x² -2x=x²-2`

    `⇔ 2x + x² -x² =-2-4`

    `⇔ 2x = -6`

    `⇔ x=-3`  `(TMĐK)`

    `c)`

    `x/(x+2)-(x²+1)/(x²-2x-8)=3/(x-4)`    `(`ĐKXĐ `x\ne -2` ;`x \ne 4“)`

    `⇔x/(x+2)-(x²+1)/(x²-2x-8)-3/(x-4)=0`

    `⇔ (x(x-4)-(x²+1)-3(x+2))/((x+2).(x-4))=0`

    `⇒ x² -4x-x²-1 -3x -6=0`

    `⇔ -7x -7=0`

    `⇔ -7x=7`

    `⇔ x=-1` `(TMĐK)`

    `d)`

     `x/(2x+1)-2/(x-3)=(x²+5)/(2x ²-5x-3)`    `(`ĐKXĐ `x\ne -0,5` ;`x \ne 3“)`

    `⇔ (x(x-3)-2(2x+1))/((2x+1).(x-3))=(x²+5)/((2x+1).(x-3)` 

    `⇒ x² -3x-4x -2=x²+5`

    `⇔ x² -x² -7x=5 +2`

    `⇔ -7x=7`

    `⇔ x=-1`  `(TMĐK)`

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  2. Đáp án:

    `↓↓`

    Giải thích các bước giải:

    A,`7/(x+2)+2/(x+3)=1/(x²+5x+6)`     (ĐKXĐ `x≠-2 ;x≠-3)`

    `⇔  (7(x+3)+2(x+2))/((x+2).(x+3))=1/((x+2)(x+3))`

    `⇒7x+21+2x+4=1`

    `⇔ 9x +25 =1`

    `⇔9x=-24`

    `⇔x=-83` `(TMĐK)`

    B, `4/(x-2)+x/(x+1)=(x²-2)/(x²-x-2)`    `(ĐKXĐ` `x≠-1 ;x≠2)`

    `⇔(4(x+1)+x(x-2))/((x-2)(x+1))=(x²-2)/((x+1)(x-2))`

    `⇒4x+4+x²-2x=x²-2`

    `⇔2x+x²-x²=-2-4`

    `⇔2x=-6`

    `⇔x=-3`  `(TMĐK)`

    C, `x/(x+2)-(x²+1)/(x²-2x-8)=3/(x-4)`    (ĐKXĐ`x≠-2 ;x≠4)`

    `⇔x/(x+2)-(x²+1)/(x²-2x-8)-3/(x-4)=0`

    `⇔ (x(x-4)-(x²+1)-3(x+2))/((x+2).(x-4))=0`

    `⇒x²-4x-x²-1-3x-6=0`

    `⇔-7x-7=0`

    `⇔-7x=7`

    `⇔x=-1“(TMĐK)`

    D,`x/(2x+1)-2/(x-3)=(x²+5)/(2x ²-5x-3)` `(ĐKXĐ` `x≠-0,5 ;x≠3)`

    ⇔ `(x(x-3)-2(2x+1))/((2x+1).(x-3))=(x²+5)/((2x+1).(x-3)`

      `⇒x²-3x-4x-2=x²+5`

    `⇔x²-x²-7x=5+2`

    `⇔-7x=7`

    `⇔x=-1`  `(TMĐK)`

    Học tốt!!!

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