Giải Pt a- 4x-3/x-5 = 29/3 b- 2x-1/5-3x = 2 c- 4x-5/x-1 = 2+ x/x-1 d- 2x+5/2x – x/x+5 = 0 e- 12/1-9xmũ2 = 1-3x/1+3x – 1+3x/1-3x Ai giúp e vs ạ hứa vot

Đáp án:

 1) x=8

Giải thích các bước giải:

\(\begin{array}{l}
1)DK:x \ne 5\\
\frac{{4x – 3}}{{x – 5}} = \frac{{29}}{3}\\
 \to 12x – 9 = 29x – 145\\
 \to 17x = 136\\
 \to x = 8\left( {TM} \right)\\
2)DK:x \ne \frac{5}{3}\\
\frac{{4x – 5}}{{5 – 3x}} = 2\\
 \to 4x – 5 = 10 – 6x\\
 \to 10x = 15\\
 \to x = \frac{3}{2}\left( {TM} \right)\\
3)DK:x \ne 1\\
\frac{{4x – 5}}{{x – 1}} = \frac{{2 + x}}{{x – 1}}\\
 \to 4x – 5 = 2 + x\\
 \to 3x = 7\\
 \to x = \frac{7}{3}\left( {TM} \right)\\
4)DK:x \ne \left\{ { – 5;0} \right\}\\
\frac{{2x + 5}}{{2x}} – \frac{x}{{x + 5}} = 0\\
 \to 2{x^2} + 15x + 25 – 2{x^2} = 0\\
 \to 15x =  – 25\\
 \to x =  – \frac{5}{3}\left( {TM} \right)\\
5)DK:x \ne  \pm \frac{1}{3}\\
\frac{{12}}{{\left( {1 – 3x} \right)\left( {1 + 3x} \right)}} = \frac{{1 – 6x + 9{x^2} – 1 – 6x – 9{x^2}}}{{\left( {1 – 3x} \right)\left( {1 + 3x} \right)}}\\
 \to  – 12x = 12\\
 \to x =  – 1\left( {TM} \right)
\end{array}\)