Toán Giải pt : $\frac{6}{x^2-1}$ +5=$\frac{8x-1}{4x+4}$ -$\frac{12x-1}{4-4x}$ 08/10/2021 By Parker Giải pt : $\frac{6}{x^2-1}$ +5=$\frac{8x-1}{4x+4}$ -$\frac{12x-1}{4-4x}$
`6/(x^2-1)+5=(8x-1)/(4x+4)-(12x-1)/(4-4x)` `6/(x^2-1)+5=(8x-1)/(4x+4)+(12x-1)/(4x-4)` `⇒24+20(x^2-1)=(8x-1)(x-1)+(12x-1)(x+1)` `⇔24+20x^2-20=8x^2-9x+1+12x^2+11x-1` `⇔2x-4=0` `⇔x-2=0` `⇔x=2` Trả lời
`6/(x^2-1)+5=(8x-1)/(4x+4)-(12x-1)/(4-4x)`
`6/(x^2-1)+5=(8x-1)/(4x+4)+(12x-1)/(4x-4)`
`⇒24+20(x^2-1)=(8x-1)(x-1)+(12x-1)(x+1)`
`⇔24+20x^2-20=8x^2-9x+1+12x^2+11x-1`
`⇔2x-4=0`
`⇔x-2=0`
`⇔x=2`