giúp em với ạ tí nx là nộp bài rồi
phân tích thành nhân tử
a/ 9x ² – 1/4
b/ (a – b) ² – 1
c/ (3x – 2y) ² – (2x – 3y) ²
d/ ( a ² + 4) ² – 16a ²
e/4x ² – 12xy + 9y ²
f/ (x+y) ² – 2(x + y) + 1
g/ $x^{6}$ – y ³
h/ x ³ – 3x ² + 3x – 1
giúp em với ạ tí nx là nộp bài rồi
phân tích thành nhân tử
a/ 9x ² – 1/4
b/ (a – b) ² – 1
c/ (3x – 2y) ² – (2x – 3y) ²
d/ ( a ² + 4) ² – 16a ²
e/4x ² – 12xy + 9y ²
f/ (x+y) ² – 2(x + y) + 1
g/ $x^{6}$ – y ³
h/ x ³ – 3x ² + 3x – 1
$a, 9x^{2}-$ $\frac{1}{4}$
=$(3x)^{2}-$ $(\frac{1}{2})^2$
=$(3x^{}+$ $\frac{1}{2})$. $(3x^{}-$ $\frac{1}{2})$
$b, (a-b)^2-1$
=$(a-b-1)(a-b+1)^{}$
$c, (3x-2y)^{2}-$ $(2x-3y)^{2}$
=$(3x-2y+2x-3y)(3x-2y-2x+3y)^{}$
=$(5x-5y)(x+y)^{}$
=$5(x-y)(x+y)^{}$
=$5(x^{2}-y^2)$
$d, (a^{2}+4)^2-16a^2$
=$(a^{2}+4+4a)(a^2+4-4a)$
=$(a+2)^{2}(a-2)^2$
$e, 4x^{2}-12xy+9y^2$
=$(2x)^{2}-2.2x.3y+(3y)^2$
=$(2x-3y)^{2}$
$f,(x+y)^{2}-2(x+y)+1$
=$(x+y)^{2}-2(x+y).1+1$
=$(x+y-1)^{2}$
$g,x^{6}-y^3$
=$(x^{2})^3-y^3$
=$(x^{2}-y)(x^4+x^2y+y^2)$
$h,x^{3}-3x^2+3x-1$
=$x^{3}-3x^2.1+3x.1^2-1$
=$(x+1)^{3}$
a/ 9x ² – $\frac{1}{4}$
= (3x)² – ($\frac{1}{2}$)²
= (3x – $\frac{1}{2}$)(3x + $\frac{1}{2}$)
b/ (a – b) ² – 1
= (a – b – 1)(a – b + 1)
c/ (3x – 2y) ² – (2x – 3y) ²
= (3x – 2y – 2x + 3y)(3x – 2y + 2x – 3y)
= (x + y)(5x – 5y)
= 5(x + y)(x – y)
d/ ( a ² + 4) ² – 16a ²
= (a² + 4)² – (4a)²
= (a² – 4a + 4)(a² + 4a + 4)
= (a – 2)².(a + 2)²
e/4x ² – 12xy + 9y ²
= (2x)² – 2.2x.3y + (3y)²
= (2x – 3y)²
f/ (x+y) ² – 2(x + y) + 1
= (x + y)² – 2(x + y).1 + 1²
= (x + y – 1)²
g/ $x^{6}$ – y ³
= $x^{2.3}$ – y³
= (x²)³ – y³
= (x² – y)($x^{4}$ + x²y + y²)
h/ x ³ – 3x ² + 3x – 1
= (x – 1)³