Giúp Mình Lần V $\mathop {\lim }\limits_{x \to 1^-} \dfrac{x+1}{x-1}$ 18/10/2021 Bởi Eliza Giúp Mình Lần V $\mathop {\lim }\limits_{x \to 1^-} \dfrac{x+1}{x-1}$
$\mathop {\lim }\limits_{x \to 1^-} \dfrac{x+1}{x-1}=\dfrac{2}{0^-}=-\infty$
lim x+1/x-1 = 2/0^- = – ∞