Giup mk câu này nha, tuy nhìn hơi rối Cho M= 1/3 + 1/16 + 1/19 + 1/21+ 1/64 + 1/72 + 1/83 + 1/94

Giup mk câu này nha, tuy nhìn hơi rối
Cho M= 1/3 + 1/16 + 1/19 + 1/21+ 1/64 + 1/72 + 1/83 + 1/94

0 bình luận về “Giup mk câu này nha, tuy nhìn hơi rối Cho M= 1/3 + 1/16 + 1/19 + 1/21+ 1/64 + 1/72 + 1/83 + 1/94”

  1. Đáp án:

     $ \dfrac{1}{3}+\dfrac{1}{16}+\dfrac{1}{19}+\dfrac{1}{21}+\dfrac{1}{64}+\dfrac{1}{72}+\dfrac{1}{83}+\dfrac{1}{94}<\dfrac{3}{5}$

    Giải thích các bước giải:

    $64<72<83<94\\
    \Rightarrow \dfrac{1}{64}>\dfrac{1}{72}>\dfrac{1}{83}>\dfrac{1}{94}\\
    \dfrac{1}{72}<\dfrac{1}{64}\\
    \dfrac{1}{83}<\dfrac{1}{64}\\
    \dfrac{1}{94}<\dfrac{1}{64}\\
    \Rightarrow \dfrac{1}{64}+\dfrac{1}{72}+\dfrac{1}{83}+\dfrac{1}{94}<4.\dfrac{1}{64}<\dfrac{4}{60}=\dfrac{1}{15}\\
    \dfrac{1}{16}>\dfrac{1}{19}>\dfrac{1}{21}\\
    \Rightarrow \dfrac{1}{16}+\dfrac{1}{19}+\dfrac{1}{21}<3.\dfrac{1}{16}<3.\dfrac{1}{15}=\dfrac{3}{15}\\
    \Rightarrow \dfrac{1}{3}+\dfrac{1}{16}+\dfrac{1}{19}+\dfrac{1}{21}+\dfrac{1}{64}+\dfrac{1}{72}+\dfrac{1}{83}+\dfrac{1}{94}<\dfrac{1}{15}+\dfrac{3}{15}+\dfrac{1}{3}=\dfrac{3}{5}$

    Bình luận
  2. Đáp án:

     $\text{Chúc bạn học tốt}$

    Giải thích các bước giải:

     $M=\dfrac{1}{3}+\dfrac{1}{16}+\dfrac{1}{19}+\dfrac{1}{21}+\dfrac{1}{64}+\dfrac{1}{72}+\dfrac{1}{83}+\dfrac{1}{94}$

    $⇒M=\dfrac{1}{3}+(\dfrac{1}{16}+\dfrac{1}{19}+\dfrac{1}{21})+(\dfrac{1}{64}+\dfrac{1}{72}+\dfrac{1}{83}+\dfrac{1}{94})$

    Xét $\dfrac{1}{16}+\dfrac{1}{19}+\dfrac{1}{21}$

    $⇒\dfrac{1}{16}+\dfrac{1}{19}+\dfrac{1}{21}<\dfrac{1}{15}+\dfrac{1}{15}+\dfrac{1}{15}$

    $⇒\dfrac{1}{16}+\dfrac{1}{19}+\dfrac{1}{21}<3×\dfrac{1}{15}$

    $⇒\dfrac{1}{16}+\dfrac{1}{19}+\dfrac{1}{21}<\dfrac{1}{5}$

    Xét $\dfrac{1}{64}+\dfrac{1}{72}+\dfrac{1}{83}+\dfrac{1}{94}$

    $⇒\dfrac{1}{64}+\dfrac{1}{72}+\dfrac{1}{83}+\dfrac{1}{94}<\dfrac{1}{60}+\dfrac{1}{60}+\dfrac{1}{60}+\dfrac{1}{60}$

    $⇒\dfrac{1}{64}+\dfrac{1}{72}+\dfrac{1}{83}+\dfrac{1}{94}<4×\dfrac{1}{60}$

    $⇒\dfrac{1}{64}+\dfrac{1}{72}+\dfrac{1}{83}+\dfrac{1}{94}<\dfrac{1}{15}$

    Do đó:$M<\dfrac{1}{3}+\dfrac{1}{5}+\dfrac{1}{15}$

    $⇒M<\dfrac{3}{5}$

    Vậy đpcm

    Bình luận

Viết một bình luận