giúp nha so sánh A = $\frac{2019}{2020}$ + $\frac{2020}{2021}$ và B = $\frac{2019+2020}{2020+2021}$ 03/10/2021 Bởi Isabelle giúp nha so sánh A = $\frac{2019}{2020}$ + $\frac{2020}{2021}$ và B = $\frac{2019+2020}{2020+2021}$
Đáp án: Ta có:2019+2020/2020+2021=2019/2020+2021 +2020/2020+2021 Vì 2019/2020+2021<2019/2020 2020/2020+2021<2020/2021 =>2019/2020+2020/2021>2019/2020+2021+2020/2020+2020=2019+2020/2020+2021 HAY A>B Bình luận
Đáp án:Giải thích các bước giải: $\color{red}{Lemon .}$ Xét : $A=\dfrac{2019}{2020}+$ $\dfrac{2020}{2021}.$ Ta có : $\dfrac{2019}{2020}>$ $\dfrac{2019}{2020+2021}$ $\dfrac{2020}{2021}>$ $\dfrac{2020}{2020+2021}$ $⇒A=\dfrac{2019}{2020}+$$\dfrac{2020}{2021}>$$\dfrac{2019}{2020+2021}$$\dfrac{2020}{2020+2021}=$$\dfrac{2019+2020}{2020+2021}=B$ vậy A > B . Bình luận
Đáp án:
Ta có:2019+2020/2020+2021=2019/2020+2021 +2020/2020+2021
Vì 2019/2020+2021<2019/2020
2020/2020+2021<2020/2021
=>2019/2020+2020/2021>2019/2020+2021+2020/2020+2020=2019+2020/2020+2021
HAY A>B
Đáp án:Giải thích các bước giải:
$\color{red}{Lemon .}$
Xét : $A=\dfrac{2019}{2020}+$ $\dfrac{2020}{2021}.$
Ta có : $\dfrac{2019}{2020}>$ $\dfrac{2019}{2020+2021}$
$\dfrac{2020}{2021}>$ $\dfrac{2020}{2020+2021}$
$⇒A=\dfrac{2019}{2020}+$$\dfrac{2020}{2021}>$$\dfrac{2019}{2020+2021}$$\dfrac{2020}{2020+2021}=$$\dfrac{2019+2020}{2020+2021}=B$
vậy A > B .