Giups mik câu này ạ $\frac{6^{3}+3.6^{2}+3^{3}}{13}$ 01/07/2021 Bởi Camila Giups mik câu này ạ $\frac{6^{3}+3.6^{2}+3^{3}}{13}$
`(6^{3}+3.6^{2}+3^{3})/13``=(3^3 . 2^3 + 3.2^2 . 3^2 + 3^3)/13``= (3^3 . 2^3 + 2^2 + 1 )/13` `= [3^3 (2^3 + 2^2 + 1 )]/13` `= [3^3 (8 + 4 + 1 )]/13` `= (3^3 . 13)/13` `= 3^3` `= 27` Bình luận
`(6^3 + 3.6^2 + 3^3)/13` `= ((2 . 3)^3 + 3 . (3 . 2)^2 + 3^3)/13` `= (2^3 . 3^3 + 3 . 3^2 . 2^2 + 3^3)/13` `= (2^3 . 3^3 + 3^3 . 2^2 + 3^3)/13` `= (3^3 . (2^3 + 2^2 + 1))/13` `= (27 . 13)/13` `= 27` Bình luận
`(6^{3}+3.6^{2}+3^{3})/13`
`=(3^3 . 2^3 + 3.2^2 . 3^2 + 3^3)/13`
`= (3^3 . 2^3 + 2^2 + 1 )/13`
`= [3^3 (2^3 + 2^2 + 1 )]/13`
`= [3^3 (8 + 4 + 1 )]/13`
`= (3^3 . 13)/13`
`= 3^3`
`= 27`
`(6^3 + 3.6^2 + 3^3)/13`
`= ((2 . 3)^3 + 3 . (3 . 2)^2 + 3^3)/13`
`= (2^3 . 3^3 + 3 . 3^2 . 2^2 + 3^3)/13`
`= (2^3 . 3^3 + 3^3 . 2^2 + 3^3)/13`
`= (3^3 . (2^3 + 2^2 + 1))/13`
`= (27 . 13)/13`
`= 27`