Given a rectangular ABCD.A’B’C’D’. Its base is a rectangular with BD = 5 cm; AB = 3cm. The lateral area of this rectangular box if BC’ = √41 cm

Given a rectangular ABCD.A’B’C’D’. Its base is a rectangular with BD = 5 cm; AB = 3cm. The lateral area of this rectangular box if BC’ = √41 cm

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  1. Đáp án:

     

    Giải thích các bước giải:

    Phythagorean theorem:

    ⇒ BD²=AB²+AD²

    ⇒AD²=BD²-AB² = 5² – 3²=16

    ⇒AD=√16=4 (cm)

    BC=AD=4 (cm)

    Phythagorean theorem:

    ⇒CC’=√BC’²-BC²=4√2 (cm)

    The lateral area of this rectangular:

    2CC’.(BC+AB)= 56√2 (cm²)

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