Given a rectangular ABCD.A’B’C’D’. Its base is a rectangular with BD = 5 cm; AB = 3cm. The lateral area of this rectangular box if BC’ = √41 cm
Given a rectangular ABCD.A’B’C’D’. Its base is a rectangular with BD = 5 cm; AB = 3cm. The lateral area of this rectangular box if BC’ = √41 cm
Đáp án:
Giải thích các bước giải:
Phythagorean theorem:
⇒ BD²=AB²+AD²
⇒AD²=BD²-AB² = 5² – 3²=16
⇒AD=√16=4 (cm)
BC=AD=4 (cm)
Phythagorean theorem:
⇒CC’=√BC’²-BC²=4√2 (cm)
The lateral area of this rectangular:
2CC’.(BC+AB)= 56√2 (cm²)